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Probability obtuse triangle - simple one

  1. Jun 30, 2012 #1
    1. The problem statement, all variables and given/known data

    The two sides lengths of a triangle is exponentially distributed. (not so important for my question)

    The angle between the sides is uniformly distributed [0,2∏]

    c) explain why the probability to get obtuse triangle is greater then 0.5

    3. The attempt at a solution

    i don't understand why it is grater then 0.5 and not exactly 0.5...
     
  2. jcsd
  3. Jun 30, 2012 #2

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    Hi wuid! :smile:

    Looks like the question is the probability to get any obtuse angle in the triangle (also considering the other 2 angles)...
     
  4. Jun 30, 2012 #3
    i am missing something... to get obtuse triangle is that the probability of the angle to be between [∏/2,3∏/2] so what i thought is : what is the probability that θ is within the II or III quarter of the plane so it is P(II)+P(III) = 0.25 + 0.25 = 0.5.

    where i am wrong ?
     
  5. Jun 30, 2012 #4

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    What about the other 2 angles of the triangle?

    Suppose your angle is acute, but one side is very long while the other side is very short.
    What kind of triangle would you have?
     
  6. Jun 30, 2012 #5
    obtuse triangle :)
    so without calculation, can i say that the probability is greater than 0.5, because that i get obtuse angle with probability 0.5 but i need to add a measure of probability that the other two angles would sum up with the first on to 180 degrees ? gives that the triangle is obtuse.
     
  7. Jun 30, 2012 #6

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  8. Jun 30, 2012 #7
    I never see the all picture...
    thank you !
     
  9. Jun 30, 2012 #8

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    You're welcome! :wink:
     
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