Probability of a state given the partition function

Join the discussion
Registration is free. Ask a follow-up in this thread, or start your own.
5 replies · 2K views
Sat D
Messages
10
Reaction score
3
Homework Statement
Given the partition function of an ideal monoatomic gas, what is the probability that its energy is some ##cU##, where ##U## is the average energy of the ensemble
Relevant Equations
##Z = \frac{1}{N!} \left( \frac{2\pi m k_B T}{h^2} \right)^{3N/2} V^N##
If my partition function is for a continuous distribution of energy, can I simply say that the probability of my ensemble being in a state with energy ##cU## is ##e^{-\beta cU} /Z##? I believe that isn't right as my energy distribution is continuous, and I need to be integrating over small intervals.
 
Physics news on Phys.org
So,
$$p(E) = \int \delta(E-cU) \frac{e^{-\beta E(\Gamma)}}{Z} d\Gamma$$
where ##\Gamma## is the phase-space.
However, how do I simplify something like this?
 
Last edited:
  • Like
Likes   Reactions: vanhees71