SUMMARY
The probability of drawing two balls of the same color from a box containing 2 red, 4 white, and 4 green balls is calculated by considering each color's probabilities. For red, the probability is calculated as $\frac{2}{10} \cdot \frac{1}{9}$. For white and green, the probabilities are both $\frac{4}{10} \cdot \frac{3}{9}$. The total probability of drawing two balls of the same color is the sum of these probabilities: $$\frac{2}{10} \cdot \frac{1}{9} + \frac{4}{10} \cdot \frac{3}{9} + \frac{4}{10} \cdot \frac{3}{9}$$ which simplifies to a definitive result.
PREREQUISITES
- Basic understanding of probability theory
- Knowledge of combinatorial counting principles
- Familiarity with drawing without replacement
- Ability to perform basic arithmetic operations with fractions
NEXT STEPS
- Study the concept of conditional probability in depth
- Learn about combinatorial probability and its applications
- Explore the concept of drawing with and without replacement
- Investigate more complex probability scenarios involving multiple events
USEFUL FOR
Students of probability, educators teaching probability concepts, and anyone interested in understanding the mechanics of drawing objects from a finite set.