Probability of Fair coin tossed

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The discussion centers on the probability of a fair coin being tossed, specifically addressing discrepancies between a student's solution and the manual solution for part B of a homework assignment. The student identifies that for the range 0 ≤ y < 1, the only valid value is y = 0, leading to the conclusion that (x-3)^2 = 0, resulting in x = 3. This highlights the importance of correctly interpreting the constraints of the problem to arrive at the correct solution.

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Homework Statement



image.png


Homework Equations



My solution for part B is different than the manual solution , here is the Manual solution :
image.png


The Attempt at a Solution


and this is my solution :
image.png
 
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ecesiu said:

Homework Statement



image.png


Homework Equations



My solution for part B is different than the manual solution , here is the Manual solution :
image.png


The Attempt at a Solution


and this is my solution :
image.png

For 0 ≤ y < 1, you must exclude the value y = 1, so you just have y = 0; that is, (x-3)^2 = 0, or x = 3. Similarly for the other values.

RGV
 

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