Probability Q using Stirling's Formula

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SUMMARY

The discussion focuses on calculating the probability of splitting a group of 2N women and 2N men into two equal halves, each containing exactly N women and N men. The solution involves using the hypergeometric distribution, where M represents the total population (4N), M1 and M2 represent the number of women and men (both N), and n is the sample size (N). Additionally, the discussion emphasizes the application of Stirling's Formula to approximate values for large N, which is essential for simplifying calculations in combinatorial problems.

PREREQUISITES
  • Understanding of hypergeometric distribution
  • Familiarity with Stirling's Formula
  • Basic combinatorial principles
  • Knowledge of probability theory
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  • Study the derivation and applications of the hypergeometric distribution
  • Learn how to apply Stirling's Formula for approximating factorials
  • Explore combinatorial proofs related to probability distributions
  • Investigate the implications of large sample sizes in probability calculations
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Mathematicians, statisticians, and students studying probability theory, particularly those interested in combinatorial problems and statistical distributions.

dspampi
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Suppose that there is a large group of people, consisting of exactly 2N women and 2N men. The group is split in half at random. What is the probability that each half contains exactly N women and N men?

And the second part asks for a given N, set up Stirling's Formula so you can calculate the approx value for a given N.

I am having trouble thinking how to set up this problem. I know as N gets bigger, the possible combinations increase...I'm thinking 2^n.
I also know that the order does not matter, but with each selection you are taking removing someone from the pool of 4N people.
 
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dspampi said:
Suppose that there is a large group of people, consisting of exactly 2N women and 2N men. The group is split in half at random. What is the probability that each half contains exactly N women and N men?

And the second part asks for a given N, set up Stirling's Formula so you can calculate the approx value for a given N.

I am having trouble thinking how to set up this problem. I know as N gets bigger, the possible combinations increase...I'm thinking 2^n.
I also know that the order does not matter, but with each selection you are taking removing someone from the pool of 4N people.

You want a _hypergeometric_ distribution here. The hypergeometric describes the following: given a population of M items, M1 of type 1 and M2 of type 2, suppose you extract a a sample of n items at random without replacement. What is the probability your sample contains exactly k items of type 1? In your case, M = 2N, M1 = M2 = N, n = N and k = N. There are standard formulas for the hypergeometric distribution.

RGV
 

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