Probability Question -- Choosing red and white coins from two tables

  • Thread starter Thread starter nothing909
  • Start date Start date
  • Tags Tags
    Probability
Click For Summary
SUMMARY

The probability of selecting a white coin from table 2 after transferring a coin from table 1 is calculated to be 21/56. Initially, table 1 contains 3 red and 5 white coins, while table 2 has 4 red and 2 white coins. The probability of selecting a white coin from table 1 is 5/8, which affects the composition of table 2. The final calculation incorporates both scenarios of transferring a white or red coin from table 1 to table 2.

PREREQUISITES
  • Understanding of basic probability concepts
  • Familiarity with conditional probability
  • Knowledge of fractions and simplification
  • Ability to apply probability rules in multi-step problems
NEXT STEPS
  • Study conditional probability and its applications in real-world scenarios
  • Learn about Bayes' theorem for more complex probability problems
  • Explore combinatorial probability to understand selection processes
  • Practice problems involving multiple events and their probabilities
USEFUL FOR

Students studying probability theory, educators teaching statistics, and anyone interested in solving complex probability problems.

nothing909
Messages
168
Reaction score
4

Homework Statement


table 1 has 3 red and 5 white coins. table 2 has 4 red and 2 white coins. a coin is chosen at random without knowing its color from table 1 and placed onto table 2. then as coin is taken from the second table. what is the probability that the coin chosen from the second table is white?

Homework Equations

The Attempt at a Solution


The answer is 21/56, but, I'm unsure how to work this out.

What I have tried is:

there is a 5/8 probability of a white coin being taken from table 1 and placed onto table 2.

then, from table 2, I assumed that the white coin from table 1 has been added, so, now there is 3 white coins on table 2.

I then did 3x(5/8) / 7, which gives me 15/56.
 
Physics news on Phys.org
nothing909 said:
there is a 5/8 probability of a white coin being taken from table 1 and placed onto table 2.
then, from table 2, I assumed that the white coin from table 1 has been added, so, now there is 3 white coins on table 2.
I then did 3x(5/8) / 7, which gives me 15/56.
This is ok. Now there is also a probability that a red coin was taken from table 1 and onto table 2.
 

Similar threads

  • · Replies 1 ·
Replies
1
Views
571
  • · Replies 3 ·
Replies
3
Views
2K
  • · Replies 23 ·
Replies
23
Views
4K
  • · Replies 3 ·
Replies
3
Views
2K
  • · Replies 7 ·
Replies
7
Views
2K
Replies
4
Views
5K
  • · Replies 5 ·
Replies
5
Views
3K
  • · Replies 9 ·
Replies
9
Views
2K
  • · Replies 2 ·
Replies
2
Views
1K
  • · Replies 21 ·
Replies
21
Views
4K