Probability Question - Exponential Distribution

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SUMMARY

The discussion centers on calculating the probability for a random variable X with an exponential distribution and mean μ, specifically P(μ-σ≤X≤μ+σ). It is established that the standard deviation σ of an exponential distribution equals its mean μ. Therefore, the bounds for the probability calculation simplify to P(0 ≤ X ≤ 2μ). The conclusion is that the probability is not zero, as the range encompasses a significant portion of the distribution.

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  • Basic skills in interpreting probability density functions
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  • Learn how to calculate probabilities using cumulative distribution functions (CDF)
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GreenPrint
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Homework Statement



Suppose that X has an exponential distribution with mean μ. Find the probability that x lies within one standard deviation of its mean, that is find P(μ-σ≤X≤μ+σ)

Homework Equations





The Attempt at a Solution



If I'm not mistaken the standard deviation is equal to the mean of an exponential distribution so isn't the answer just zero or am I missing something important here?
 
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GreenPrint said:

Homework Statement



Suppose that X has an exponential distribution with mean μ. Find the probability that x lies within one standard deviation of its mean, that is find P(μ-σ≤X≤μ+σ)

Homework Equations





The Attempt at a Solution



If I'm not mistaken the standard deviation is equal to the mean of an exponential distribution so isn't the answer just zero or am I missing something important here?

Yes. You are missing the facts that μ-σ = 0 and μ+σ = 2μ, so you want P(0 ≤ X ≤ 2μ). Why would you suppose that is 0?
 
oh thanks i missed that
 

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