Probability that a Year with 53 Sundays is a Leap Year?

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SUMMARY

The probability that a year with 53 Sundays is a leap year is calculated using conditional probability. A leap year has 366 days, which allows for the possibility of 53 Sundays. The correct approach involves determining the probability of having 53 Sundays in both leap and non-leap years. The formula for leap years is approximately 1/4, adjusted for century years, leading to the conclusion that the conditional probability p(B|A) requires knowledge of both p(A|B) and p(A|¬B).

PREREQUISITES
  • Understanding of conditional probability
  • Knowledge of leap year rules (Gregorian calendar)
  • Basic probability concepts
  • Familiarity with probability notation (e.g., p(A|B))
NEXT STEPS
  • Study conditional probability in depth
  • Learn about the Gregorian calendar and leap year calculations
  • Explore probability distributions and their applications
  • Review examples of conditional probability problems
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Students studying probability theory, educators teaching mathematics, and anyone interested in understanding the nuances of leap years and their statistical implications.

sheldonrocks97
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Homework Statement


A year has 53 Sundays. What is the conditional probability that it is a leap year.

Homework Equations


None that I can think of.

The Attempt at a Solution


I tried by knowing that a leap year has 366 days. Next we can note that the remaining 2 days could be sunday and monday, monday and tuesday, ... and saturday and sunday. Sunday appears 2 out of 7 times, so the answer I got was 2/7. Is that correct or did I do something wrong?
 
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You forgot the conditional part.
If A = 53 Sundays and B= Leap Year, you found p(A|B). You want p(B|A).
You still need to know the probability of 53 Sundays on a non-leap year.
 
To answer this you need to use knowledge of how often leap years occur. The questioner probably expects you to use 1/4, but strictly speaking it's (1/4-1/100+1/400).
 

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