Probability theory: a regenerative process

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Homework Help Overview

The discussion revolves around a problem in probability theory, specifically focusing on a regenerative process related to the expected lifetime of a car cycle and its resale value based on certain probabilities.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • Participants are attempting to calculate the expected time of a cycle and the expected resale value of a car based on its lifespan. Questions are raised about how to incorporate probabilities into these calculations, particularly regarding the definitions of events related to the car's failure or survival.

Discussion Status

Some participants have provided insights into calculating expected values and have discussed the implications of different events on resale value. There is an ongoing exploration of how to determine the probability of events and their impact on the overall calculations, with no explicit consensus reached yet.

Contextual Notes

Participants are navigating the complexities of conditional expectations and the relationship between lifespan and resale value, with specific attention to the definitions of failure and survival probabilities. The problem context includes constraints related to the expected costs and outcomes based on the car's performance.

dirk_mec1
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Homework Statement


http://img291.imageshack.us/img291/4844/14820448wb9.png


The Attempt at a Solution


First of all I'm trying to find the expected time of a cycle. In a cycle two things can happen:

1) the car lives long enough to reach A with probability 1-F(A)
2) the car fails to reach age A with probability F(A)

Knowing this how can you compute the liftime of a cycle? I thought of something like:

E(T) =A*(1-F(A)) + F(A) * ? (I don't know what to fill in the question mark)
 
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E(T) is the expected value of T ~ F conditional on T < A. But you can directly solve for the expected resale price:

Let event 1 be {the car fails before A}. If event 1 occurs then resale value = 0 (do you see this?)
Let event 2 be {the car lives to A} (that is, it lives to see A, and possibly more). If event 2 occurs then resale value = R(A).

Suppose the probability of event 1 was G. Convince yourself that the prob. of event 2 must be 1 - G.

Then E(resale value) = G * 0 + (1-G) * R(A).

What you should think about is how to find G.
 
EnumaElish said:
E(T) is the expected value of T ~ F conditional on T < A.
So the expected life of a cycle is: [tex]E[T|T<A] = \int_0^{A} x f(x)\ \mbox{d}x[/tex]

But you can directly solve for the expected resale price:

Let event 1 be {the car fails before A}. If event 1 occurs then resale value = 0 (do you see this?).
Yes It's stated in the exercise.

Let event 2 be {the car lives to A} (that is, it lives to see A, and possibly more). If event 2 occurs then resale value = R(A).

Suppose the probability of event 1 was G. Convince yourself that the prob. of event 2 must be 1 - G.
That's clear.

Then E(resale value) = G * 0 + (1-G) * R(A).

What you should think about is how to find G.

I presume that G must be F(A). But the question asks for the costs so how do I incorporate that in the resale value given that there are two different outcomes?
 
Once you figure the expected resale value, you can use it to figure the expected net cost, defined as cash expenses - expected resale value.
 

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