Probability Theory: Shuffling a Deck of Cards

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SUMMARY

The discussion focuses on the probability theory related to shuffling a standard deck of 52 playing cards. The sample space for the experiment of turning over the first card consists of all 52 cards, represented as S = {D-H2, D-H3, ..., D-HA}. When considering the event where the first card is a heart, the correct representation is E_H = {2h, 3h, ..., Ah}, which contains exactly 13 outcomes corresponding to the heart cards. The initial misunderstanding involved overcomplicating the event space, which should simply reflect the 13 heart cards.

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  • Understanding of basic probability concepts
  • Familiarity with sample spaces and event definitions
  • Knowledge of standard deck of playing cards
  • Basic mathematical notation and set theory
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  • Study the concept of sample spaces in probability theory
  • Learn about discrete probability distributions
  • Explore combinatorial problems involving card games
  • Investigate the principles of shuffling and randomness
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This discussion is beneficial for students of probability theory, educators teaching statistics, and anyone interested in understanding the fundamentals of card games and their associated probabilities.

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EDIT: Please disregard, or delete.
I got it.

Stumped on this question:
Shuffle a deck of cards and turn over the first card. What is the sample space of this experiment? How many outcomes are in the event that the first card is a heart?

Attempt at a solution:

D = \{ deck of 52 cards randomly shuffled \}
S = \{ x | x \in D \}

I'm not sure if this is right. The event is viewing the the first card. So if we are viewing one card, all possible cards viewable at one time would just be one of the 52 cards right? Or does the sample space need for example:

S = {D-H2, D-H3, ... D-HA, D-***,}
Where D is the 52 cards. H2 would mean two of hearts, HA would mean ace of hearts. *** would mean all other card combinations.

Next part,
"How many outcomes are in the event that the first card is a heart"

Would I define the event as,
E_H = { D-H2, D-H3, ... , D-HK, D-HA }
D-H2 would mean the set that contains 51 cards without the two of hearts.

Thus the number of elements of E_H would be: 51^13


thanks in advance
 
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You said you got it, but what you have there is not right? You should have only 13 outcomes (for the first card being a heart). The event space would just be {2h, 3h, ... 10h, Jh, Qh, Kh, Ah} where 2h = 2 of hearts, etc.
 
mattmns said:
You said you got it, but what you have there is not right? You should have only 13 outcomes (for the first card being a heart). The event space would just be {2h, 3h, ... 10h, Jh, Qh, Kh, Ah} where 2h = 2 of hearts, etc.

Yeah, I should have pointed out that what I wrote down is not right.

I realized the problem was easier then what I was trying to make it out to be.
 

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