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Precalculus Mathematics Homework Help
Probability of Getting a Total of 15 or Higher in Three Dice Throws
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[QUOTE="Seneka, post: 6075957, member: 641637"] [h2]Homework Statement [/h2] If two identical dice are thrown, what is the probability that the total of the numbers is 10 or higher? [Hint: list the combinations that can give a total of 10 or higher.] [2] Two dice have been thrown, giving a total of at least 10. What is the probability that the throw of a third die will bring the total of the three numbers shown to 15 or higher? [3] [B] 2. Homework Equations ... Actual Answer[/B] Part 1) 1/6 Part 2) 10: 5,6 11: 4,5,6 12: 3,4,5,6 (3/6 x 2/6) + (2/6 x 3/6) + (1/6 x 4/6) = 4/9 [h2]The Attempt at a Solution[/h2] So I obtained the solution to the first part by drawing a probability space diagram. Giving 1/6 For the second part I thought: If I get a total of 10 for the first two throws I will need a 5 or 6 to give at least 15 11: 4,5,6 12: 3,4,5,6P(t=10) = 3/36 P(t=11)= 2/36 P(t=12) = 1/36 2(3/36 x 1/6) + 3(2/36 x 1/6) + 4(1/36 + 1/6) = 2/27 Why am I wrong in assuming that the probability of getting a total of 10 in the first two throughs is the probability represented by the probability space diagram so 3 out of 36. What is wrong with my working? [/QUOTE]
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Probability of Getting a Total of 15 or Higher in Three Dice Throws
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