Probably easy expected value problem

Click For Summary
SUMMARY

The discussion centers on calculating the expected number of correct labels when n throat cultures are randomly paired with n people's names. The solution involves defining two random variables, X1 for names and X2 for cultures, and applying the expected value formula. The correct expected value is derived as 1, based on the probability of each label matching its corresponding culture being 1/n. The participants confirm the logic and calculations presented by Mark, validating the conclusion that the average number of correct labels is indeed 1.

PREREQUISITES
  • Understanding of random variables in probability theory
  • Familiarity with expected value calculations
  • Knowledge of probability distributions
  • Basic mathematical summation techniques
NEXT STEPS
  • Study the concept of expected value in probability theory
  • Learn about random variables and their applications
  • Explore advanced probability distributions and their properties
  • Investigate combinatorial problems related to random pairings
USEFUL FOR

Students of probability theory, mathematicians, and anyone interested in statistical analysis and expected value calculations.

mkkrnfoo85
Messages
50
Reaction score
0
Hello, just a bit insecure about my answer.

Problem:-------
Suppose n people have throat cultures, and the cultures are then completely
mixed up. If we randomly pair off the n peoples’ names with the n cultures,
what is the expected number of correct labels?
---------------

So, here's my logic on the solution:

I think there are 2 random variables here, X1 for names, X2 for the cultures.
The formula for the expected value for 2 random variables is:

[tex]\sum_1^n \sum_1^n h(X1,X2)*prob(X1,X2)[/tex] for some weight function h.

I chose h(X1,X2) = 1. Also, I said prob(X1,X2) = (1/n^2). I hope all that is right so far. So just using the expected value equation, I simply said the answer is 1.

[tex]\sum_1^n \sum_1^n (1)* \left \frac{1}{n^2} \right = 1[/tex]

Correct thinking? If not, what am I doing wrong?

Thanks in advance,

Mark
 
Last edited:
Physics news on Phys.org
N labels on N bottles.

1/N chance for label i to correspond to bottle i.

Average number of correct labels= sum_i=1,N * chance for label i
=1

So I agree.
 

Similar threads

  • · Replies 1 ·
Replies
1
Views
1K
Replies
5
Views
2K
Replies
3
Views
2K
  • · Replies 14 ·
Replies
14
Views
4K
  • · Replies 2 ·
Replies
2
Views
2K
  • · Replies 8 ·
Replies
8
Views
2K
  • · Replies 2 ·
Replies
2
Views
3K
  • · Replies 11 ·
Replies
11
Views
3K
  • · Replies 11 ·
Replies
11
Views
2K
  • · Replies 5 ·
Replies
5
Views
2K