Problem of finding the volume of a box.

  • Thread starter Thread starter naaa00
  • Start date Start date
  • Tags Tags
    Box Volume
Click For Summary

Homework Help Overview

The discussion revolves around finding the volume of a box under the constraint that the sum of its dimensions must not exceed a certain limit. The problem specifically involves maximizing the volume given a fixed height and varying width and length.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning, Problem interpretation

Approaches and Questions Raised

  • Participants explore the relationship between volume and dimensions, with attempts to express volume in terms of width and height. There are discussions about the implications of treating height as a fixed variable and the confusion surrounding the use of partial derivatives in a single-variable context.

Discussion Status

Participants are actively engaging with the problem, questioning assumptions about variable dependencies and the interpretation of the problem statement. Some guidance has been offered regarding the use of partial derivatives, but there remains a lack of consensus on the best approach to take given the constraints of the problem.

Contextual Notes

There is a noted confusion regarding the term "fixed" in relation to height, with participants questioning its implications for the variables involved in the volume calculation. Additionally, there is uncertainty about the expectations set by the textbook regarding the methods to be used.

naaa00
Messages
90
Reaction score
0

Homework Statement



The airlines accept a box if length + width + height <= 62. If h is fixed, show that the maximum volume (62-w-h)wh is V = h(31 - h/2)^2.

The Attempt at a Solution



Well, I multipied:

V(h) = (62-w-h)wh
V(h) = 62wh - w^2h - wh^2

dv/dt = 62w - w^2 - 2w = 60w - w^2

0 = 60w - w^2
w = 60.

But this can not be. This is wrong. I tried other things but all of my attemps are wrong...
 
Physics news on Phys.org
What you have done makes no sense at all. You write "V(h)" when V depends on both w andh as variables. And then you write "dv/dt" when there is NO "t" variable at all!

A differentiable function of two variables will have max or min only where its gradient is 0 or, equivalently, \partial V/\partial w= 0 and \partial V/\partial h= 0.
 
Thank you for your answer, HallsofIvy.

"dv/dt" well, yes. That was a typo from my part. My bad. Clearly volume does not depent on t...

I see that you have written partial derivative notation. I am assuming that your suggestion is to use partials, since volume seems to depend on two variables, namely h and w. But this exercise is in a problem set of a single-variable calculus textbook. I guess this can be solved that way, but for the moment I think the textbook expects me to solve the problem without the aid of partials. (I don't know know anything of partials. I only know something about its notation.)

My thought is that since V = HLW, I would get something of the form V = h times M^2, if I assume L = W = M^2, and then substitute. But I don't know how to prove this assumption and I have the feeling that it is wrong...
 
Last edited:
But the problem statement says h is fixed. I am not sure what does the textbook means with "fixed" (I am not an english native speaker.) I suppose it means that h is not a variable, since it is "fixed"; it does not change. If that is the case, then V depends on L and W. But the problem ask me to show that (62-w-h)wh is V = h(31 - h/2)^2. Here "V" seems to be in function of h; a some sort of contradiction. I am a little bit confused...
 
Well, certainly I was confused yesterday. Happily now I undestand the problem:

V = (62 - h - w)wh,

V = 64wh - h^2w - w^2h.

dv/dw = 62h - h^2 - 2wh,

0 = 62h - h^2 - 2wh,

w = 62h - h^2/ 2h

w = 31 - h/2.

It turns out that L = W, because L = 62 - h - w, or L = 62 - h - (31 - h/2), or L = 31 - h/2.

Then, if we let W^2 = LW, it is clear that V = W^2H. Finally we have (31 - h/2)^2 times h.

Thanks! See you next time!
 

Similar threads

  • · Replies 9 ·
Replies
9
Views
3K
Replies
1
Views
2K
  • · Replies 3 ·
Replies
3
Views
2K
  • · Replies 33 ·
2
Replies
33
Views
3K
  • · Replies 3 ·
Replies
3
Views
2K
Replies
7
Views
2K
  • · Replies 1 ·
Replies
1
Views
2K
  • · Replies 20 ·
Replies
20
Views
3K
  • · Replies 4 ·
Replies
4
Views
2K
  • · Replies 13 ·
Replies
13
Views
29K