Problem of fluid -- Blocks, pulley, two fluids

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Homework Help Overview

The problem involves analyzing a system of blocks and pulleys interacting with two fluids, focusing on dynamic viscosity and force balances. The original poster attempts to determine the weight of one block and the speed of another while considering the effects of fluid dynamics and neglecting friction in the pulley.

Discussion Character

  • Exploratory, Assumption checking, Problem interpretation

Approaches and Questions Raised

  • The original poster describes two approaches to the problem but notes discrepancies in the results. They question their understanding of the force balances on the blocks, particularly regarding the tangential forces due to the fluids and the components of weight acting on block 2.

Discussion Status

Some participants provide feedback on the original poster's force balance calculations, indicating that there may be misunderstandings in how the forces are applied to block 2. There is an ongoing exploration of the correct interpretation of forces acting on the blocks, particularly in relation to the fluid dynamics involved.

Contextual Notes

Participants are discussing the implications of neglecting friction in the pulley and how this affects the force balances. There is also a focus on the correct identification of forces acting in different directions and the assumptions made regarding the interactions between the blocks and the fluids.

Queren Suriano
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Homework Statement


dynamic viscosity 1 = 1125 2 kgf-s / m2 , dynamic viscosity 2 = 62.5 2 kgf-s / m2 , Areas: A1 = 20 cm2 , A2 = 50 cm2
W1 = 15 Kgf, W2 = 40 Kgf.
The block (2) is displaced downwards with a
constant speed of 80 mm / sec, whereas
linear velocity distribution determined:
1) The weight of the block (3).
2) The speed of the block (1).
Neglect friction in the pulley
upload_2015-3-3_12-13-33.png

upload_2015-3-3_12-25-39.png


Homework Equations


the angle is 30º
(tangencial force) / area = (dynamic viscosity) (velocity/space betwteen the two surfaces)

sum forces=0 (Equilibrium)

The Attempt at a Solution



I did the problem of two ways, considering each block and considering the system, but I don't get the same answer.

What am I doing wrong??
 
Last edited:
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Your force balance on block 2 is incorrect, and your force balance on the overall system is incorrect. Your calculated value of F2 is correct. The force balance for the overall system should be the sum of the force balances on the individual blocks.

Chet
 
I don't understand why the force balance on block 2 is incorrect?? Because in the block 2 acts two tangetial forces due the fluid, and the component horizontal of the weight
 
Queren Suriano said:
I don't understand why the force balance on block 2 is incorrect?? Because in the block 2 acts two tangetial forces due the fluid, and the component horizontal of the weight
It should include only the component of the weight of block 2, not both blocks.

Chet
 
Chestermiller said:
It should include only the component of the weight of block 2, not both blocks.

Chet
But the block 2 support the block 1, if I only consider the weight of block 2, it's just like the block 2 was alone, but it doesnt
 
Queren Suriano said:
But the block 2 support the block 1, if I only consider the weight of block 2, it's just like the block 2 was alone, but it doesnt
The weight of block 1 exerts a force on block 2 in the normal direction, but block 1 is not exerting a force on block 2 in the tangential direction. The fluid in the gap between block 1 and block 2 is exerting a force on block 2 in the tangential direction, but you've already included that in your force balance.

Chet
 

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