Problem on distribution of charges between charged/uncharged spheres

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SUMMARY

The discussion centers on the distribution of electric charges between three spherical conductors: A (uncharged), B, and C (both charged). When conductor A contacts B, the charge is evenly distributed, resulting in B and A each having Q/2. Subsequently, when A contacts C, the total charge of 3Q/2 is equally distributed, leading to each conductor having 3Q/4. The final force of repulsion between B and C is calculated to be 3F/8, based on Coulomb's law.

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Homework Statement



2 Spherical conductors B and C having equal radii and carrying equal charges repel each other with force F. Another conductor A having same radius as B but uncharged is brought into contact with B, and then C and then removed from both.

Find the new force of repulsion between B and C. (Answer should be 3F/8)


Homework Equations



Coulomb's law


The Attempt at a Solution



Since when an uncharged sphere A contacts with B, the charges from B flow over, leaving B with half of the charges, and A with half of the charges (initial assumption).

Afterwards charged A contacts C, but i am not quite sure about the distribution of charges from here on. Since now A have half of the original charges, does it mean that 1/4 of the charges of C will flow into A to equalise?

Or is my initial assumption that A will get half of the charges from B wrong in the first place?

Any help is much appreciated.
 
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I think the charge is going to equalise. So you can just add the charge of A and C and divide it by 2 to get the total charge on each one.

So, let's say A has 0 and B and C have Q.
A touches B so they both have Q/2.
A touches C. The charge distributes equally. So, total charge is 3Q/2. So, there will be 3Q/4 on each one.
So, you're right.
 

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