Problem reading thermodynamic tables

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At a given temperature, the state of a substance can be determined by its pressure relative to the saturation pressure. If the pressure is lower than the saturation pressure, the substance exists as overheated vapor, while if the pressure is higher, it is in a compressed liquid state. When pressure increases in a mixture of liquid and vapor, excess vapor condenses into liquid until only liquid remains, allowing for further pressure increases. Conversely, decreasing pressure causes some liquid to evaporate into vapor until only vapor remains, leading to a superheated state. Understanding these principles is crucial for interpreting thermodynamic tables effectively.
Sly37
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Hi!
I have trouble understanding this:
Given Temperature:
If pressure < saturation pressure => Overheated Vapor
If pressure > saturation pressure =>Compressed Liquid


Why does this happen??

Thanks in advance!
 
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At a given temperature, you can have both pure vapor and pure liquid present together in equilibrium if the pressure is equal to the equilibrium vapor pressure at that temperature. If you try to increase the pressure by reducing the volume of a fixed amount of liquid and vapor, you won't be able to do it. You will just cause some of the vapor to condense and form more liquid. However, eventually, you will cause all the vapor to condense. After that you will be able to increase the pressure, since only liquid will be remaining.

If you try to decrease the pressure by increasing the volume of a fixed amount of liquid and vapor, you won't be able to do ti. You will just cause some of the liquid to evaporate and form more vapor. However, eventually, youwill cause all the liquid to evaporate. After that, you will be able to reduce the pressure, since only vapor will be remaining. This will be referred to as superheated vapor.
 
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