Problem using Pulleys with Weight in Equilibrium

Click For Summary
SUMMARY

The discussion centers on solving a physics problem involving pulleys, tension, and equilibrium. Participants emphasize the importance of free body diagrams (FBDs) to analyze forces acting on a hanging weight and the mast. The correct approach involves isolating the hanging mass to determine tension (T) in relation to weight (W) and using component equations to find the angle (X) of the mast. A potential error in the original problem's diagram regarding the angle reference is also highlighted.

PREREQUISITES
  • Understanding of free body diagrams (FBDs)
  • Knowledge of Newton's laws of motion
  • Familiarity with tension and weight forces in equilibrium
  • Basic trigonometry for angle calculations
NEXT STEPS
  • Study the principles of static equilibrium in physics
  • Learn how to construct and analyze free body diagrams
  • Explore examples of tension in pulley systems
  • Review trigonometric functions related to angles in physics problems
USEFUL FOR

Students studying physics, educators teaching mechanics, and engineers working with pulley systems will benefit from this discussion.

Tygra
Messages
55
Reaction score
8
Homework Statement
Calculate angle of mast and the compression force in the mast
Relevant Equations
In the question
Dear all,

I have the following problem:

Screenshot 2024-10-30 230737.png

I need to find the compression "C" in the mast and the angle that the masts makes with the horizontal (X degrees).

I know that the tension in the ropes "T" are of the same magnitude on both sides of the pulley, but I am struggling with finding C and X.

Could someone help please?
 

Attachments

  • Screenshot 2024-10-30 225617.png
    Screenshot 2024-10-30 225617.png
    5.3 KB · Views: 70
  • Screenshot 2024-10-30 230624.png
    Screenshot 2024-10-30 230624.png
    5.2 KB · Views: 71
Physics news on Phys.org
If nothing is moving, all forces are in balance.
What have you done so far in terms of free body diagrams?
 
Hi Lnewqban,

this is how I attempt the question:

Screenshot 2024-10-30 232846.png

When I do the final algebra, I am way off.
 
Tygra said:
Hi Lnewqban,

this is how I attempt the question:

View attachment 352905
When I do the final algebra, I am way off.
Please share a Free body diagram of the hanging weight, and a separate FBD of the mast.
 
Lnewqban said:
It seems that the original diagram shows the top 45° angle in error, as its reference should be a vertical line rather than C.
So are you saying they did this on purpose?

Can I ask, how you would attempt this question?
 
No, I don’t.
Yes, you can: a free body diagram would be my very first step.
 
Lnewqban said:
No, I don’t.
Yes, you can: a free body diagram would be my very first step.
So it must be a typo in the book? This problem is from a book.

Here is my free body diagram:

Screenshot 2024-10-31 124011.png


Is this correct?
 
Tygra said:
So it must be a typo in the book? This problem is from a book.

Here is my free body diagram:

View attachment 352917

Is this correct?
FBD of what? You isolate the hanging mass. Forces of weight ##W## and tension(s) ##T## act on it. You use it to find ##T## in terms of ##W##. Thats one FBD. The other is a Free body diagram of the member ##C##. You isolate the mast from the external surroundings. Tension forces, and reaction forces at the hinge should be shown. You use both component equations simultaneously to find the angle ##X##.
 
  • #10
Thank you. I have it now. I think I was making it more complicated than what it was.
 
  • #11
Tygra said:
So it must be a typo in the book? This problem is from a book.

Here is my free body diagram:

View attachment 352917

Is this correct?
Yes, it must be a typo.
Otherwise they would be giving away angle x as being 90° (45+45+90=180), which is an incorrect value.

In order to properly calculate T, you need to consider the “Y” formed by T, T and 5 kN.
In this case the “Y” is symmetrical and the value of T is the same on the left and the right sides, but it is not always that way.
Hope you have checked the example in the link previously posted.
 
  • Like
Likes   Reactions: erobz

Similar threads

  • · Replies 2 ·
Replies
2
Views
3K
  • · Replies 11 ·
Replies
11
Views
3K
  • · Replies 3 ·
Replies
3
Views
3K
Replies
1
Views
4K
  • · Replies 31 ·
2
Replies
31
Views
4K
Replies
25
Views
9K
  • · Replies 23 ·
Replies
23
Views
3K
  • · Replies 8 ·
Replies
8
Views
3K
  • · Replies 5 ·
Replies
5
Views
4K
  • · Replies 22 ·
Replies
22
Views
6K