Problem with 2 cars on almost masless spining platform

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The discussion centers on the physics of two cars on a nearly massless spinning platform, examining the effects of angular momentum and frame of reference. Participants analyze the scenario where both cars initially move radially and then turn 90 degrees, questioning how this affects the platform's rotation and energy conservation. Key conclusions include that energy and momentum are conserved within a closed system, but their values are frame-dependent. The conversation highlights the importance of selecting an appropriate inertial frame for accurate analysis.

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  • Familiarity with inertial and non-inertial reference frames
  • Basic knowledge of kinetic energy calculations
  • Concept of fictitious forces in physics
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  • #31
Dale said:
Are you assuming that they are "coasting" through the turn, I.e. Doing 0 work with their legs?

Yes they are coasting and doing zero work with their legs.
 
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  • #32
Then assuming the skates are frictionless on the ice, kinetic energy is conserved. I believe that is the whole point of your setup. You want the skaters to turn while conserving kinetic energy.

So what unknowns do you have, and what constraints and conservation principles can you use?
 
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  • #33
I have to keep constant the initial kinetic energy which would be 0.5*200*1=100

And angular momentum that would be zero

So 0=mvr-Iw=200*v*1-iw=0
So 200v=Iw
So supposing the platform has such a shape as to have a moment of inertia equal to 2 then
200v=w

So now i balance energy:
100=0.5*200*v^2+1w^2
100=100v^2+w^2
so 100-100v^2=w^2
substituting:
100-100v^2=40000v^2
so 100=40100v^2
v=0.05 m/s
so w=100

Would this be correct?
 
  • #34
The approach is correct. I haven't checked the arithmetic, but even if you made an error there you have the concept right.
 

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