Problem with Approximations Using Differentials

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The discussion revolves around solving a problem involving approximations using differentials to find the component of a force at an angle with potential errors. The initial calculations yielded incorrect results due to misapplication of trigonometric functions and errors in the differential equations. After identifying the mistakes, particularly in the use of sine and cosine, the correct approach was applied, leading to the accurate component error of 4.28 nt. The importance of trusting one’s original diagram and understanding the correct application of trigonometric identities was emphasized. Ultimately, the correct solution was achieved through careful reevaluation of the calculations.
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Homework Statement


I am working on this problem and having difficulty getting the required answer. It is the exact problem as here , but I’m still not getting it.

BTW this is problem 10, Section 4, Chapter 4 Partial Differentiation from M. Boas’s book Mathematical Methods in the Physical Sciences, 3rd edition.

A force 500 nt is measured with a possible error of 1 nt. Its component in a direction 60° away from its line of action is required, where the angle is subject to an error of 0.5°. What is (approximately) the largest possible error in the component?

Homework Equations

The Attempt at a Solution


We are going to use differentials here.

##Component = F_1*sin(\theta)##

##\frac{d Component}{Component} = \frac {d F_1}{F_1} + \frac {d sin(\theta)}{sin(\theta)} d \theta##

##\frac{d Component}{Component} = \frac {d F_1}{F_1} + \frac {cos(\theta)}{sin(\theta)} d \theta##

##Largest \left|\frac{d Component}{Component}\right| = \left|\frac {d F_1}{F_1}\right| + \left|\frac {cos(\theta)}{sin(\theta)} d \theta\right| = \frac{1}{500}+\frac{cos(\frac{\pi}{3})}{sin(\frac{\pi}{3})} * \frac{0.5}{60} = .002 + cot(\frac{\pi}{3}) * \frac{0.5}{60} = .002 + 0.00481 = 0.00681##

So the ##Component = 500 sin(\frac{\pi}{3}) = 433##

##Component Error = 433*0.00681 = 2.95## … which is not the correct answer of 4.28 nt

So if someone can direct me to my error I'd certainly appreciate it! Thank you!
 
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You have used ##d\theta/\theta## instead of ##d\theta## in your computation. Note that you also need to put it in radians based on how you treated the derivative.
 
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Thank you Orodruin! Let me put your ideas in motion!

##Largest \left|\frac{d Component}{Component}\right| = \left|\frac {d F_1}{F_1}\right| + \left|\frac {cos(\theta)}{sin(\theta)} d \theta\right| = \frac{1}{500}+\frac{cos(\frac{\pi}{3})}{sin(\frac{\pi}{3})} * \frac{0.5\pi}{180} = .002 + cot(\frac{\pi}{3}) * \frac{0.5\pi}{180} = .002 + 0.00504 = 0.00704##

So the ##Component = 500 sin(\frac{\pi}{3}) = 433##

##Component Error = 433*0.00704 = 3.05## … which is still not the correct answer of 4.28 nt

So I suspect there's something seriously wrong with my approach ... my equation ... any further ideas that could lead me to a correct solution please? :-) Thank you!
 
What is the component of a force in a direction to which it makes an angle ##\theta##?
 
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Yes, thank you so much! I looked at my original diagram and realized that I had the trig wrong! Shame on me! I was mislead a bit by the ref thread. I should have trusted my original diagram and not listened to the banter on that thread.
IMG_0248.jpg

To correct this:
##Largest \left|\frac{d Component}{Component}\right| = \left|\frac {d F_1}{F_1}\right| + \left|\frac {sin(\theta)}{cos(\theta)} d \theta\right| = \frac{1}{500}+\frac{sin(\frac{\pi}{3})}{cos(\frac{\pi}{3})} * \frac{0.5\pi}{180} = .002 + tan(\frac{\pi}{3}) * \frac{0.5\pi}{180} = .002 + 0.0151 = 0.0171##

So the ##Component = 500 nt\hspace{.1cm} cos(\frac{\pi}{3}) = 250 nt##

##Component Error = 250 nt*0.0171 = 4.28 nt## … which is the correct answer.##\hspace{1cm}\square##
 

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Question: A clock's minute hand has length 4 and its hour hand has length 3. What is the distance between the tips at the moment when it is increasing most rapidly?(Putnam Exam Question) Answer: Making assumption that both the hands moves at constant angular velocities, the answer is ## \sqrt{7} .## But don't you think this assumption is somewhat doubtful and wrong?

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