Problem with equation of line tangent to curve

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Homework Help Overview

The discussion revolves around finding the equation of the tangent line to a curve at a specific point, utilizing the derivative calculated in a previous part of the problem. The subject area includes calculus, specifically the concepts of derivatives and tangent lines.

Discussion Character

  • Exploratory, Mathematical reasoning

Approaches and Questions Raised

  • Participants discuss different forms of the equation of a line, questioning the use of the slope-intercept form (y=mx+b) and suggesting alternative forms. There is an emphasis on ensuring the correct application of the slope and point coordinates.

Discussion Status

Some participants have offered guidance on using the point-slope form of the equation for the tangent line, indicating that the original poster has already identified the slope and point of tangency. There is a recognition of potential errors in the calculations, but no consensus has been reached on the final form of the equation.

Contextual Notes

The original poster expresses frustration with the acceptance of their answer, suggesting there may be specific requirements or constraints in the problem that have not been fully addressed.

Chas3down
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Homework Statement


Now use your answer from part (a)(This anwser is f'(25) = 7/10, which is correct) to find the equation of the tangent line to the curve at the point (25, f(25)).


Homework Equations


f(x) = 7*sqrt(x)+3



The Attempt at a Solution


f'(25) = 7/10
f(25) = 38
y=mx+b
38=7/10*25+b

y=7/10x + 41/2

This should be the correct answer... but it won't accept it.


if you want to view the entire problem, http://i.imgur.com/xtVehti.png
 
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Try using something other than y=mx+b. Do you know any other ways to write the equation that doesn't rely on B?
 
Yosty22 said:
Try using something other than y=mx+b. Do you know any other ways to write the equation that doesn't rely on B?

we are given y= ?

so y=mx+b is really the only linear function they could be looking for.
 
Try y-y_1=m(x-x_1). You are given y_1 and x_1 (or can easily find them) and you have already solved for m. The rest is plugging in and simplifying.
 
Yosty22 said:
Try y-y_1=m(x-x_1). You are given y_1 and x_1 (or can easily find them) and you have already solved for m. The rest is plugging in and simplifying.

edit: i am an idiot... had a - instead of a +
 

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