Problem with equation / proving formula

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The discussion centers around proving the formula v_{0} = \frac{M+m}{m}\sqrt{2gus} using the equation \frac{m^2v_{0}^2}{2(M+m)} = gmus. The user attempts to manipulate the equation but expresses uncertainty about the validity of their calculations, particularly regarding the right-hand side. There is speculation about a possible error in the textbook, with a mention of 'u' as the coefficient of friction relevant to the context of kinetic energy and work. The conversation highlights confusion over the formula's derivation and the potential for mistakes in the source material. The thread emphasizes the importance of verifying mathematical steps and understanding the underlying physics concepts.
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Homework Statement


I have to prove some formula, I got stuck in the process.

Homework Equations


Formula to prove:
v_{0} = \frac{M+m}{m}\sqrt{2gus}
Valid equation that should get me to this formula:
\frac{m^2v_{0}^2}{2(M+m)} = gmus

The Attempt at a Solution


v_{0}^2=\frac{2(M+m)}{m^2}gmus
v_{0}^2 = \frac{M+m}{m}2gus
v_{0} = \sqrt{\frac{M+m}{m}2gus}

I'm pretty sure my math has failed me here, that right handside of the equation seems fishy, or maybe book did a mistake?
 
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You seem to be correct may be there is a mistake in the book, what is u?
 
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Yeah I'm probably going to assume that there's a mistake in the book, u is the coefficient of friction, this equation is the given equation of kinetic energy = work where the force is the force of friction.
 
The book claims the answer is that all the magnitudes are the same because "the gravitational force on the penguin is the same". I'm having trouble understanding this. I thought the buoyant force was equal to the weight of the fluid displaced. Weight depends on mass which depends on density. Therefore, due to the differing densities the buoyant force will be different in each case? Is this incorrect?

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