Problem with Feynman Rule for Vertices

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SUMMARY

The discussion centers on deriving Feynman rules for vertices using 't Hooft’s diagrammar and the methodology outlined in Cheng and Lee's "Gauge Theory of Elementary Particle Physics." The user encountered discrepancies between their results and those presented in a referenced Arxiv paper. The correct approach involves considering the interaction terms in the Lagrangian and applying functional derivatives until no fields remain, yielding the Feynman rule for that vertex. An example provided illustrates the process with the term ieγμψ̄ψAμ, resulting in the Feynman rule ieγμ.

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  • Understanding of Feynman rules in quantum field theory
  • Familiarity with 't Hooft’s diagrammar
  • Knowledge of Lagrangian mechanics in particle physics
  • Experience with functional derivatives in theoretical physics
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  • Study the derivation of Feynman rules from interaction terms in various Lagrangians
  • Explore 't Hooft’s diagrammar in detail for practical applications
  • Learn about functional derivatives and their role in quantum field theory
  • Review Cheng and Lee's "Gauge Theory of Elementary Particle Physics" for deeper insights
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This discussion is beneficial for theoretical physicists, graduate students in particle physics, and researchers focusing on quantum field theory and Feynman diagram techniques.

Neitrino
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Dear PF,
I would like to thank you for existence of Physics forums since it appears very helpful.

Dear PF,
I was reading one paper and trying to derive Feynman rules for some vertices, but I could not get the same result as given in paper, as a guideline I use ‘t Hooft’s diagrammar and the same is given in appendices of Cheng and Lee – Gauge Theory of elementary particle physics. I attach extract from one Arxiv paper, extract from diagrammar and what I was trying to write.
Could you please have a look and advise me what I do wrong?

Thank you in advance.
 

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Dear all,
Could anyone pls give some feedback... May be my question senseless...
some advise pls...
 
I asked a similar thing in a thread a while back.

https://www.physicsforums.com/showthread.php?t=135689

Basically you just consider the 'interaction terms' in the Lagrangian and then take the functional derivatives till you have no more fields left in that term. The remaining quantity is the Feynman rule for that vertex.

For instance, suppose you have the term [tex]ie\gamma^{\mu}\bar{\psi}\psi A_{\mu}[/tex], then taking the functional derivatives would leave you with [tex]ie\gamma^{\mu}[/tex], that's the Feynman rule. Just remember that if you've something like [tex]e\phi^{2}\psi[/tex] you'll pick up the factor of 2 from differentiating [tex]\phi^{2}[/tex] twice. I know it sounds obvious but you won't believe how often slip ups like that throw a spanner in the works!
 

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