Problem with hyperbolic functions demostrations

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SUMMARY

The discussion focuses on proving the identity cosh(\frac{x}{2}) = \sqrt{\frac{cosh(x)+1}{2}} using hyperbolic functions. The relevant equation provided is cosh(x) = \frac{e^{x}+e^{-x}}{2}. The attempted solution involves manipulating the expression but lacks clarity in the final steps. The correct approach confirms that cosh^2(\frac{x}{2}) simplifies to \frac{cosh(x)+1}{2}, establishing the identity definitively.

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  • Basic algebraic manipulation skills
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Homework Statement


Prove that [itex]cosh (\frac{x}{2}) = \sqrt{\frac{cosh(x)+1}{2}}[/itex]


Homework Equations


[itex]cosh(x) = \frac{e^{x}+e^{-x}}{2}[/itex]



The Attempt at a Solution


[itex]\frac{\sqrt{e^{x}}+\sqrt{e^{-x}}}{2} \ast \frac{\sqrt{e^{x}}-\sqrt{e^{-x}}}{\sqrt{e^{x}}-\sqrt{e^{-x}}} \rightarrow \frac{e^{x}+e^{-x}}{2} \ast \frac{1}{\sqrt{e^{x}}-\sqrt{e^{-x}}} \rightarrow cosh(x) \ast \frac{1}{\sqrt{e^{x}}-\sqrt{e^{-x}}}[/itex]

After that, I don't know what to do. Would be glad if somebody would tell me what I'm doing wrong or how to do it. Thanks.
 
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[tex] cosh^2\frac{x}{2}=\frac{e^x+e^{-x}+2}{4}=\frac{cosh(x)+1}{2}[/tex]
That's it!
 

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