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## Homework Statement

Calculate the average vector velocity between 0 and pi/4 sec.

## Homework Equations

x=rcos2t

y=rsin2t

Vx=2rsin(2t)

Vy=2rcos2t

Ax=4rcos(2t)

Ay=-4cos(2t)

Circular path is x^2+y^2+r^2

## The Attempt at a Solution

I'm not sure if I am missing something simple or not, What I need to know is what is r and so I initially set the square of the x and the square of the y equations equal to the square r. Pythagorean style. when I solved for r I felt just a little dumb because I got 1=1 which well duh I shoul've saw that coming. Now I'm trying to guess whether I even need r to do an average, or if there is another way to solve for r that I am missing. I also know that x=r when t=0 but when I sub r for x in the position equation I just get 1.