Problem with photoelectric effect

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The discussion revolves around solving a problem related to the photoelectric effect, specifically determining the largest wavelength of light that can still emit electrons from a photosurface. The participant correctly applies the equation eV = hf - W, leading to a calculated work function of approximately 7.7 x 10^-19 J, which corresponds to a maximum wavelength of 2.6 x 10^-7 m (or 272 nm). Clarification is provided that as long as the frequency of incoming photons is above the threshold frequency, or the wavelength is shorter than the threshold wavelength, electrons will be emitted. There is no minimum wavelength restriction, but higher potential would be needed for shorter wavelengths. The participant acknowledges confusion over terminology but ultimately confirms the key points about photon energy and electron emission.
ant284
Hi,

I'm have a problem with photoelectric effect
it states that we have a wavelength of 2.08*10^-7 falls on the photosurface, a voltage of 1.40V is required to stop the emitted electrons from reaching the anode.
What is the largest wavelength of light which will result in emission of electrons from this photosurface.?

so we have the equation
eV=hf-W
W=h* critical frequency and
K=hf-W
and
f=speed of light/wavelength.

v=1.40
f=(3*10^8)/(2.08*10^-7)

And wouldn't the Kinetic energy be 0 for a wavelength of 2.08*10^-7
So i don't know where to go from here! I want to do it but I can't it is frustrating!
Any help is appreciation
 
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Hi again,

I think i got it

we have
K(kinetic)= eV
eV=hf-W
1.4 * (1.6*10-19) = h c/wavenlength -work
we get work =
7.7*10^-19 (About)
Now when it is the largest value above this value no electron will be emitted therefore KE=0
so we would have
0= Hc/waveleng-W
or
hc/w=wavelength
and we get 2.6*10^-7

But my question what would be the minimum value of wavelength?? if it is possible to find
 
Your answer to the question is right (I got 272 nm without rounding). As for a minimum wavelength - there isn't really a restriction on how short wavelength the light is aslong as it is shorter than the threshold (maximum) wavelength. It's just that a higher potential would be needed to stop emission.
 
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Hi,

one more quick question, as long as the frequency is below the threshold electrons are emitted, and above the threshold, the electrons are not emitted? Am i correct
 
Damn sorry I've probably just confused you now. I've editted my original to say wavelength instead of frequency (oops). Aslong as the photons are above the threshold frequency, or below the wavelength at this frequency will there be emission. Sorry I kept swapping wavelength and frequency and probably confused us both!

Anyway to make it clear again - aslong as the photons are above the threshold frequency, or have a shorter wavelength than the wavelength at this frequency there will be electron emission. So there is really no minimum wavelength value. lol :wink:

editted: about 10 times for spelling and grammar
 
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The book claims the answer is that all the magnitudes are the same because "the gravitational force on the penguin is the same". I'm having trouble understanding this. I thought the buoyant force was equal to the weight of the fluid displaced. Weight depends on mass which depends on density. Therefore, due to the differing densities the buoyant force will be different in each case? Is this incorrect?

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