What is the largest wavelength for emission of electrons from a photosurface?

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Homework Help Overview

The discussion revolves around the photoelectric effect, specifically focusing on determining the largest wavelength of light that can cause electron emission from a photosurface, as well as calculating the work function based on stopping voltages for different wavelengths of light.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • The original poster attempts to calculate the largest wavelength for electron emission and the work function using given wavelengths and stopping voltages. Some participants question the relationship between wavelength and energy of emitted electrons, while others suggest looking into the principles of the photoelectric effect.

Discussion Status

The discussion is ongoing, with participants exploring the relationships between wavelength, frequency, and energy. Some guidance has been offered to look up the photoelectric effect, but no consensus or resolution has been reached yet.

Contextual Notes

Participants are working within the constraints of specific wavelengths and stopping voltages provided in the original post, which may limit the exploration of broader concepts related to the photoelectric effect.

prakriti
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1) when light of wavelength 2.08*10^-7m falls on a photosurface, a voltage of 1.40V is required to stop the emitted electrons from reaching the anode. What is the largest wavelength of light that will result in emission of electrons from this photosurface?


2) To determine the work function of given photosurface, light of wavelength 2.3*10^-7 m is directed at the surface and the stopping voltage is recorded. When light of wavelength 1.8*10^-7m large as the previous one. Find the work function.
 
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What is the relationship between the wavelength of the incident light and the energy of the emitted electrons?
 
isnt it f = speed / wavelength
and Energy = h*f
so Energy = h*speed/wavelength
but i just can't figure out the problem.. please help!
 
look up the photoelectric effect
 

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