# Homework Help: Problem with this question(lenear algebra)

1. Mar 2, 2009

### transgalactic

Last edited by a moderator: May 4, 2017
2. Mar 2, 2009

### yyat

B) You found correctly that Ker(T) consists of vectors of the form (x,0,0,0). This can can be written as Ker(T)=span{(1,0,0,0)}.
Regarding the image of T: Your solution is correct, but one can also find a simpler basis consisting of standard basis vectors.

C) Look at the system of linear equations you extracted from the matrix equation, there is a small error. Also, since T has a one-dimensional kernel there will be infinitely many solutions.

3. Mar 2, 2009

### transgalactic

regarding B i get 0*x=0
on what basis i can state that its
(x,0,0,0)
??

where is the error in C
??

4. Mar 2, 2009

### yyat

Well, you are trying to find all possible values of x,y,z,t so that T((x,y,z,t))=0. You found that this means that 0=x*0, y=0, z=0, t=0. So x can be any number (0=x*0 is true for all x) and y,z,t have to be zero. So the solutions of the equation T((x,y,z,t))=0 are exactly the vectors of the form (x,0,0,0), where x is any number.

The first equation, x+2y=2, should be y+2z=2.