Process Control (transfer function) problem

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SUMMARY

The discussion centers on determining the output response y(t) of a series RL circuit given the transfer function and an input signal x(t) = u(t) V. The user initially associates the transfer function with F(s) = 1/(s+a) but later realizes it should be a/s+a, where a = R/L. The community advises on using proper notation, defining u(t), and comparing y(t) values at t=0 and t=∞ to eliminate incorrect options.

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  • Understanding of transfer functions in control systems
  • Familiarity with series RL circuits
  • Knowledge of the Laplace transform
  • Ability to analyze first-order lag systems
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  • Study the derivation of transfer functions for RL circuits
  • Learn about the properties of the Laplace transform
  • Explore first-order system responses and their characteristics
  • Investigate the significance of the unit step function u(t) in control theory
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Electrical engineering students, control systems engineers, and anyone involved in analyzing dynamic systems and transfer functions.

guiromero
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TL;DR Summary: transfer function

Hello,

I have a doubt on this exercise from my post graduation course:
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The transfer funtion of a series RL circuit is given by:

1706903438830.png

Determine the answer y(t) for an entry signal given by x(t) = u(t) V:

1706903562428.png

__________________________________________________________________________________________________

From the Laplace table, I find the closest association would be e-at, for F(s) = 1/s+a. Then the answer would be "d", but I'm not sure if this association is correct, because F(s) is not exactly 1/s+a, it's more likely a/s+a, where a = R/L.

Could someone give me a clear answer?

Thanks a lot!
 
Physics news on Phys.org
1) Use parentheses. If you mean 1/(s+a), then write 1/(s+a), not 1/s + a. Correct all those errors.
2) Define u(t).
3) Compare the y(t) values at ##t=0## and ##t=\infty## of the optional answers with what you would expect from a first order lag transformation, H(s). That should rule out practically all the wrong answers.
 

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