Product of Exponential Form (easy)

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Homework Help Overview

The discussion revolves around the multiplication of complex exponentials represented in exponential form, specifically focusing on the expression e^{i\theta_1}e^{i\theta_2} and its equivalence to e^{i(\theta_1 + \theta_2)}. Participants are examining the real and imaginary components derived from the multiplication of their corresponding trigonometric forms.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • Participants are attempting to multiply the trigonometric forms of the complex exponentials and are questioning the correctness of their results. There is confusion regarding the signs in the resulting expressions and the application of fundamental properties of complex numbers.

Discussion Status

The discussion is ongoing, with participants providing insights and questioning each other's reasoning. Some guidance has been offered regarding the use of trigonometric identities, but there is no clear consensus on the misunderstanding or the correct approach yet.

Contextual Notes

Participants express uncertainty about basic principles related to complex numbers and their multiplication, indicating a potential gap in foundational knowledge. There is a concern about conflicting information between personal notes and textbook references.

DEMJ
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Homework Statement



[tex]e^{i\theta_1}e^{i\theta_2} = e^{i(\theta_1 + \theta_2)}}[/tex]

Homework Equations


The Attempt at a Solution



For some reason every I multiply [tex](cos\theta_1 + isin\theta_1)(cos\theta_2 + isin\theta_2)[/tex] I am getting

[tex](cos\theta_1 cos\theta_2 + sin\theta_1 sin\theta_2) + i(sin\theta_1 cos\theta_2 + cos\theta_1 sin\theta_2)[/tex]

according to my book the first part should be [tex](cos\theta_1 cos\theta_2 - sin\theta_1 sin\theta_2)[/tex]

what am I missing here? Is it some basic fundamental from calculus I have forgotten?

What I am doing is [tex]cos\theta_1 cos\theta_2 - (isin\theta_1)(isin\theta_2) = cos\theta_1 cos\theta_2 - i^2 sin\theta_1 sin\theta_2[/tex] since [tex]i^2 = -1[/tex] that makes it positive. But this can't be right because both the book and my notes from class cannot be wrong. So please enlighten me =]
 
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[tex]e^{ix} = \cos x + i\sin x,\,\![/tex]

Substitute x=[itex]\theta_1 + \theta_2[/itex] and then use:

[tex]\sin(\alpha \pm \beta) = \sin \alpha \cos \beta \pm \cos \alpha \sin \beta \,[/tex]

[tex]\cos(\alpha \pm \beta) = \cos \alpha \cos \beta \mp \sin \alpha \sin \beta\,[/tex]
 
DEMJ said:

Homework Statement



[tex]e^{i\theta_1}e^{i\theta_2} = e^{i(\theta_1 + \theta_2)}}[/tex]


Homework Equations





The Attempt at a Solution



For some reason every I multiply [tex](cos\theta_1 + isin\theta_1)(cos\theta_2 + isin\theta_2)[/tex] I am getting

[tex](cos\theta_1 cos\theta_2 + sin\theta_1 sin\theta_2) + i(sin\theta_1 cos\theta_2 + cos\theta_1 sin\theta_2)[/tex]
For the real part you should be getting cos(th1)cos(th2) + i^2*sin(th1)sin(th2). I think you omitted the i^2 factor.
DEMJ said:
according to my book the first part should be [tex](cos\theta_1 cos\theta_2 - sin\theta_1 sin\theta_2)[/tex]

what am I missing here? Is it some basic fundamental from calculus I have forgotten?

What I am doing is [tex]cos\theta_1 cos\theta_2 - (isin\theta_1)(isin\theta_2) = cos\theta_1 cos\theta_2 - i^2 sin\theta_1 sin\theta_2[/tex] since [tex]i^2 = -1[/tex] that makes it positive. But this can't be right because both the book and my notes from class cannot be wrong. So please enlighten me =]
 
DEMJ said:
For some reason every I multiply [tex](cos\theta_1 + isin\theta_1)(cos\theta_2 + isin\theta_2)[/tex]

...What I am doing is [tex]cos\theta_1 cos\theta_2 - (isin\theta_1)(isin\theta_2) = cos\theta_1 cos\theta_2 - i^2 sin\theta_1 sin\theta_2[/tex] since [tex]i^2 = -1[/tex] that makes it positive.
Why are you subtracting? Once you answer that, you should be all set.
 

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