Product Rule vs. Quotient Rule: A Common Mistake in Differentiating Equations

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Discussion Overview

The discussion centers on the differentiation of the equation y=\frac{e^x}{x} and the comparison between using the product rule and the quotient rule. Participants explore the implications of rearranging the equation and the potential for different results based on the chosen method of differentiation.

Discussion Character

  • Debate/contested
  • Mathematical reasoning

Main Points Raised

  • One participant questions the validity of rearranging the equation to apply the product rule, suggesting it leads to different results compared to using the quotient rule.
  • Another participant asserts that both methods yield the same answer if differentiated correctly, indicating a potential misunderstanding in the application of the rules.
  • A participant proposes that treating 1/x as a negative exponent eliminates the need to view it as a quotient, thus simplifying the differentiation process.
  • One participant shares their step-by-step differentiation using the product rule and expresses uncertainty about the correctness of their solution compared to Wolfram Alpha's output.
  • Another participant challenges the need for Wolfram Alpha, suggesting that a common denominator approach would lead to the same result as the quotient rule.
  • Clarifications are made regarding the use of the product rule versus the quotient rule, with one participant emphasizing that they did not use the quotient rule in their calculations.
  • Participants discuss the arrangement of solutions provided by Wolfram Alpha, noting that it is simply a different form of the same result.

Areas of Agreement / Disagreement

Participants express differing views on the necessity and correctness of using the product rule versus the quotient rule, with some asserting that both methods should yield the same result while others remain uncertain about the implications of their approaches. The discussion does not reach a consensus on the best method to use.

Contextual Notes

Some participants express confusion regarding the outputs from Wolfram Alpha and the relationship between their own solutions and those provided by the tool. There is also mention of alternate forms of the solution that may not have been initially considered.

Who May Find This Useful

Students and individuals interested in calculus, particularly those learning about differentiation techniques and the application of product and quotient rules.

elementbrdr
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When differentiating the following equation, y=\frac{d}{dx}\frac{e^x}{x}, why is it wrong to rearrange the equation to y=\frac{d}{dx}\frac{1}{x}e^x and apply the product rule? Doing so gives me a different result than using the chain rule in conjunction with the quotient rule.

Sorry about the latex formatting, I'm still trying to get the hang of it.
 
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No, you do not get different results.
If you differentiate correctly, that is.
 
They both give the same answer. I suspect it might have something to do with your statement "...the chain rule in conjunction with the quotient rule."

When you split up the fraction to do product, there is no need to treat 1/x as a quotient. Just bring it to the numerator with a negative exponent. It gives you two fractions instead of one, but getting a common denominator results in the same fraction as the normal quotient rule.
 
hmmm, well my solution was as follows:
1. y=e^x*\frac{1}{x} //rearrange equation
2. y=e^x*\frac{1}{x}+e^x*-x^{-2} //apply product rule
3. y=\frac{e^x}{x}-\frac{e^x}{x^2} //simplify
I'm pretty sure this is incorrect, as Wolfram Alpha comes up with a different solution. Where did I mess up?
 
Last edited:
It is correct.
What did Wolfram tell you?
 
To clarify, I used the product rule to find the solution. When I used Alpha to take the derivative, it chose to use the quotient rule and reached a different solution. I did not personally use the quotient rule. Sorry for the confusion.
 
There should be no need for Wolfram Alpha. If you multiply the first fraction by x/x to get a common denominator, you get the same single fraction as you would get from the quotient rule.
 
elementbrdr said:
To clarify, I used the product rule to find the solution. When I used Alpha to take the derivative, it chose to use the quotient rule and reached a different solution. I did not personally use the quotient rule. Sorry for the confusion.

No, it did not produce a different solution.
Please post its solution, and I'll show you why it is the same as yours.
 
I'm going to beat a hasty retreat here... Here's the Wolfram solution: http://www.wolframalpha.com/input/?i=d%2Fdx+e^x%2Fx

It's just arranged differently than my solution.
 
  • #10
elementbrdr said:
I'm going to beat a hasty retreat here... Here's the Wolfram solution: http://www.wolframalpha.com/input/?i=d%2Fdx+e^x%2Fx

It's just arranged differently than my solution.
We are not here to bite you, but to help you. I'm glad you found out by your own where the problem was.

Welcome to PF! :smile:
 
  • #11
I wouldn't add anything since you already noticed it's simply a different form of the same thing, but...

just under the two graphs it gives alternate forms, including the exact one you came up with.
 
  • #12
Thanks! I really like the forum and wish I had found it years ago. Would have made college a lot easier.
 
  • #13
S_Happens, thanks, I didn't notice the alternate forms box before.
 

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