Progressive wave, wavelength moving in the opposite direction

AI Thread Summary
The discussion centers on understanding why the wavelength differs for waves moving in opposite directions. For a wave traveling in the -z direction, the wavelength is calculated to be 18 cm using the formula λ = 2π/κ, where κ is derived from the wave's angular frequency and velocity. In contrast, the wavelength for a wave moving in the +z direction is found to be 9 cm, leading to confusion about the differing results despite the same wave properties. The conversation highlights that without additional information, multiple solutions exist for the wavelength due to the periodic nature of waves, and the choice of integer n can affect the outcome. Ultimately, clarity on how to determine n is crucial for resolving the discrepancy in wavelengths.
Redwaves
Messages
134
Reaction score
7
Homework Statement
Finding the wavelength. if the wave is moving in the +z direction and -z direction.
Relevant Equations
##\Psi(z=15cm,t) = \hat{x} 6 cos (\frac{\pi}{3}t)##
##\Psi(z=12cm,t + 2s) = \Psi(z=18cm,t)##
I'm trying to find the wavelength. However, I don't understand why the wavelength is different if the wave is moving in the +z direction.

I have
##\Psi(z=15cm,t) = \hat{x} 6 cos (\frac{\pi}{3}t)##
##\Psi(z=12cm,t + 2s) = \Psi(z=18cm,t)##

For a wave moving on the -z direction

I know that the wavelength = ##\frac{2\pi}{\kappa}## and the shape of the wave is describe by this function ##x(z,t) = A cos(\omega t +\kappa z + \alpha_0)##

##\kappa = \frac{\omega}{v}, \omega = \frac{\pi}{3}## and ##v = 12-18/(t+2)-t = -3##

thus, the wavelength = ##\frac{2\pi}{\pi/9} = 18 ##, which is the right answer.

However, for a wave moving in the +z direction the wavelength is 9cm. Why is this different ?The velocity isn't the same? how can I find it.
 
Last edited:
Physics news on Phys.org
Redwaves said:
Homework Statement:: Finding the wavelength. if the wave is moving in the +z direction and -z direction.
Relevant Equations:: ##\Psi(z=15cm,t) = \hat{x} 6 cos (\frac{\pi}{3}t)##
##\Psi(z=12cm,t + 2s) = \Psi(z=18cm,t)##

I'm trying to find the wavelength. However, I don't understand why the wavelength is different if the wave is moving in the +z direction.

I have
##\Psi(z=15cm,t) = \hat{x} 6 cos (\frac{\pi}{3}t)##
##\Psi(z=12cm,t + 2s) = \Psi(z=18cm,t)##

For a wave moving on the -z direction

I know that the wavelength = ##\frac{2\pi}{\kappa}## and the shape of the wave is describe by this function ##x(z,t) = A cos(\omega t +\kappa z + \alpha_0)##

##\kappa = \frac{\omega}{v}, \omega = \frac{\pi}{3}## and ##v = 12-18/(t+2)-t = -3##

thus, the wavelength = ##\frac{2\pi}{\pi/9} = 18 ##, which is the right answer.

However, for a wave moving in the +z direction the wavelength is 9cm. Why is this different ?The velocity isn't the same? how can I find it.
In general, we are given: $$\Psi(z_1, t+ t_1) = \Psi(z_2, t)$$Which implies that$$wt_1 = k(z_2 - z_1) \pm 2\pi n$$This gives us an infinite number of solutions, depending on the direction of motion and how many wavelengths there are between the points ##z_1## and ##z_2##.

If we take ##n = 0##, then we have $$\lambda = \frac{2\pi}{k} = 2\pi\frac{z_2 - z_1}{wt_1}$$And, in this case we have $$\lambda = 18cm$$. But, as above, there are infinitely many other solutions - one for ecah value of ##n##.
 
How we know which value for n we choose? In my example., how can I know that for a wave moving in the +z direction n is -1?
 
Redwaves said:
How we know which value for n we choose? In my example., how can I know that for a wave moving in the +z direction n is -1?
You don't know. Unless you have additional information, then there are multiple solutions.
 
In my case it should have a way to find wavelength since, that what I have to find.

Edit: from the information above, I have to find the wavelength.
Tell me if I'm not clear.
 
Thread 'Collision of a bullet on a rod-string system: query'
In this question, I have a question. I am NOT trying to solve it, but it is just a conceptual question. Consider the point on the rod, which connects the string and the rod. My question: just before and after the collision, is ANGULAR momentum CONSERVED about this point? Lets call the point which connects the string and rod as P. Why am I asking this? : it is clear from the scenario that the point of concern, which connects the string and the rod, moves in a circular path due to the string...
Back
Top