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Kurokari
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Homework Statement
A motorcycle stuntman who is moving horizontally takes off from a point 15.0m above the ground and lands 60.0m
Calculate
a. Time between taking off and landing
b. the speed of the motorcycle at take-off
Homework Equations
s = ut + 1/2(at^2)
The Attempt at a Solution
Using the above equation and the information, s= 15m , initial velocity, u = 0 , a = g =9.81
the answer was 1.75s, which according to the book is correct.
My problem lies with the second part of it, it is asking me to look for the initial velocity which is at the point of taking off, but I just used u = 0.
The answer given is,
Consider horizontal motion, v = constant.
Horizontal distance = vt
v = 60.0/1.75 = 34.3ms^-1If anyone can help me solve this contradiction and explain it to me, it would really help me understand concept questions like these. Thanks in advance =)