Projectile corrections due to the coriolis effect

Click For Summary
SUMMARY

The discussion focuses on solving a projectile motion problem involving a launch angle \(\alpha\) from a height \(h\) above the ocean, with the projectile landing a distance \(d\) from the cliff base. The maximum height \(H\) of the projectile is derived using the equation \(H = H2 + \frac{d^2}{4} \tan^2 \alpha / (H + d \tan \alpha)\), while neglecting air resistance and the Coriolis effect. Participants emphasize the importance of expressing the initial speed in terms of the given variables, specifically \(V_{\text{initial}}^2/g\), to facilitate problem-solving.

PREREQUISITES
  • Understanding of projectile motion principles
  • Knowledge of trigonometric functions, particularly tangent
  • Familiarity with kinematic equations
  • Basic algebra for manipulating equations
NEXT STEPS
  • Explore the derivation of projectile motion equations
  • Study the effects of launch angles on projectile trajectories
  • Learn about the impact of air resistance on projectile motion
  • Investigate the Coriolis effect in projectile motion scenarios
USEFUL FOR

Students studying physics, particularly those focusing on mechanics and projectile motion, as well as educators seeking to enhance their teaching methods in these topics.

tarletontexan
Messages
29
Reaction score
0

Homework Statement


a projectile is launched at an angle \alpha above the horizontal, from the top of a vertical cliff of height h above the ocean. It strikes a distance d from the base of the cliff. Show that its maximum height is given by H2 +(d2/4)tan2\alpha/(H+d tan\alpha) neglecting air resistance and Coriolis effect


Homework Equations





The Attempt at a Solution


Hint: First express the initial speed in terms of the givens, i believe this to be V initial2/g since that gives you a distance. Just don't know what else to do
 
Physics news on Phys.org
The problem says to ignore coriolis effect. There's lots of ways to do this problem, so the best thing is for you to start experimenting with your own approach and then let us know where you get stuck.
 

Similar threads

Replies
7
Views
4K
  • · Replies 1 ·
Replies
1
Views
3K
Replies
3
Views
3K
  • · Replies 4 ·
Replies
4
Views
3K
  • · Replies 1 ·
Replies
1
Views
3K
  • · Replies 11 ·
Replies
11
Views
2K
  • · Replies 1 ·
Replies
1
Views
3K
  • · Replies 1 ·
Replies
1
Views
1K
  • · Replies 3 ·
Replies
3
Views
2K
  • · Replies 9 ·
Replies
9
Views
8K