A projectile is launched at an angle 45 degrees above the horizon with a velocity of 30 m/s. It is launched at the base of a constant slope, which has an angle of 30 degrees.
a- How much time did it take for the projectile to hit the slope?
b- Where did the projectile hit the slope? Use a vector.
c- Was the projectile moving up or down when it hit?
t = 2 V sin angle /g
x= V^2 sin 2angle / g
The Attempt at a Solution
a- (2(30 m/s) sin 15)/ 9.8 m/s^2
t = 1.58 s
b- (30 m/s (cos 15) ) i + (30 m/s (sin 15)) j
I am not sure I should be using 15 as the angle for part b. I tried with 30 and 45, and 30 seems like the right coordinates considering the picture I drew.