(adsbygoogle = window.adsbygoogle || []).push({}); 1. The problem statement, all variables and given/known data

If an athlete jumped 2 feet high and left the ground at an angle of 20 degrees with respect to the horizontal, how fast was the athlete going in the forward (positive horizontal) and upward (positive vertical) directions immediately after takeoff? If the height of takeoff was the same as the height of landing, how fast was the athlete going in the horizontal and vertical directions right before landing?

2. Relevant equations

vx = vcos(thata)

vy = vsin(theta)

Immediately after take off :

vx = 2cos25 = 1.8126

vy = 2sin25 = 0.845

right before landing:

vx = 2cos25 = 1.8126

vy = 2sin25 = -0.845

3. The attempt at a solution

Im not sure if my solution is correct can anyone confirm please ?

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# Homework Help: Projectile: launching and landing from the same height help me ?

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