Projectile Motion airplane engine question

Click For Summary

Homework Help Overview

The problem involves projectile motion, specifically analyzing the motion of an airplane engine that falls off while the airplane is in horizontal flight. The scenario includes calculating the height from which the engine falls and the horizontal distance it travels before hitting the ground.

Discussion Character

  • Exploratory, Assumption checking, Mathematical reasoning

Approaches and Questions Raised

  • Participants discuss the initial conditions of the engine's motion, noting its horizontal velocity matches that of the airplane while its vertical velocity is initially zero. There are inquiries about the appropriate kinematic equations to use for the problem.

Discussion Status

Some participants have made attempts to apply kinematic equations to derive the height and horizontal distance. There are indications of confusion regarding the application of these equations, with some participants expressing frustration over their understanding of the problem. A few calculations have been shared, but there is no consensus on the correctness of the approaches yet.

Contextual Notes

Participants mention a specific time duration of 30 seconds for the engine's fall and express uncertainty about the equations needed to solve for the height and distance. There is a recognition of the need for further clarification on the mathematical relationships involved.

LoveKnowledge
Messages
51
Reaction score
0
1. You're in an airplane that flies horizontally with speed 1000 km/h (280 m/s) when an engine falls off. Neglecting air resistance, assume it takes 30 s for the engine to hit the ground.

a. Show that the airplane is 4.0 km high.

b. Show that the horizontal distance that the aircraft engine falls is 8400 m

c. If the airplane somehow continues to fly as if nothing had happened, where is the engine relative to the airplane at the moment the engine hits the ground?




I am confused! I need help with this problem and the steps to formulate the solutions..
 
Physics news on Phys.org
When the engine detaches from the plane, its velocity in the horizontal direction is the velocity of the plane. But its velocity in the vertical direction id zero.
So what is the kinematic equation which relates the displacement, initial velocity, acceleration and time?
 
d=5t² ? I am just really confused about this question. I have been studying physics for several hours now and my brain is just not comprehending this for some reason when I know it should...
 
I understand the "c" part of the problem but I am still confused with "a" and "b" I know the equation d=5t² but there needs to be a further extension of this equation. I am just stuck with how I would show parts "a" and "b" with the question that it is asking me..
 
Ok I figured out for part "b" I did not need a simple equation...I really am brain dead right now! lol...280 m/s x 30 s = 8400 m

For part "a" I plugged into the equation for "d=5t² = 4 km= 5*30s²" but I don't know if I am correct..
 
d = 4.9*30^2 = 4481 m =~ 4 km.

Horizontal distance = 280*30 = ?
 

Similar threads

  • · Replies 4 ·
Replies
4
Views
2K
Replies
4
Views
3K
Replies
40
Views
3K
  • · Replies 5 ·
Replies
5
Views
5K
Replies
4
Views
2K
  • · Replies 1 ·
Replies
1
Views
2K
  • · Replies 11 ·
Replies
11
Views
2K
  • · Replies 3 ·
Replies
3
Views
4K
  • · Replies 1 ·
Replies
1
Views
2K
Replies
15
Views
3K