A rock is thrown from the top of a 26 m building at an angle of 51° above the horizontal. (a) If the horizontal range of the throw is equal to the height of the building, with what speed was the rock thrown? (b) How long is it in the air? (c) What is the velocity of the rock just before it strikes the ground? Let Vi = initial velocity X component = Vi Cos 51 Y component = Vi Sin 51 I know that without any height, I can calculate the time 0 - Vi Sin 51 = -9.81 * T T = Vi Sin 51 / 9.81 Total time in the air = 2 Vi Sin 51 / 9.81 Horizontal range = Vix * Total time in air 26 = Vi Cos 51 * 2 Vi Sin 51 / 9.81 but since there is a height involved, what changes do I need to make?