Projectile motion cannon shell problem

[Zugox]

Homework Statement

A coastal defence cannon fires a shell horizontally from the top of a 50.0m high cliff directed out to sea with a velocity of 60.0m/s.
Determine the range of the shell's trajectory.

Homework Equations

delta x = ut (horizontally)
delta y = ut + 1/2 at^2

The Attempt at a Solution

working vertically
50 = 0t + (1/2 * 9.8 * t^2)
t = 3.2

working horizontally
delta x = ut
delta x = 60 * 3.2
delta x = 192
therefore the range is 192m

I'm not too great with physics although really willing to learn and really interested in it :)
Can someone just confirm I'm right or put me on the right track

 

[MysticDude]

I haven't done the math but your work seems right, I'm studying this area in Physics class too :D

 

[Zugox]

I haven't done the math but your work seems right, I'm studying this area in Physics class too :D

I'm 99% sure on the math, was just worried about the formulas I used:)

 

[MysticDude]

Well, since we are firing horizontally, $$\theta$$ = 0 meaning $$y-y_0 = \frac{-1}{2}gt^2$$ and you have that. Then you can just plug in for $$d=vt$$ and you should get 192m.