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Projectile Motion comparing height and initial velocity

  1. Jan 12, 2012 #1
    Hey,
    I came across this question in my text book, and there isnt an answer for it in the back, so I would just like to check if I have my head around it.

    The question is:
    2 projectiles are launched at the same angle. Projectile 1 reaches a max height of twice that of the projectile 2. What is the ration of the initial speeds?

    I said that they where in the ratio 4:1, as one of the formulas is: y=yo +voyt -0.5gt^2
    and because the height is doubled, the time taken must also be doubled?
    am I correct in saying this?

    Thanks
     
  2. jcsd
  3. Jan 12, 2012 #2

    Doc Al

    User Avatar

    Staff: Mentor

    No.

    Come up with a formula that relates max height with initial velocity without the need for the time.
     
  4. Jan 12, 2012 #3
    I got an answer or root(2), is this correct?
     
  5. Jan 12, 2012 #4

    Doc Al

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    Staff: Mentor

    Yes.
     
  6. Jan 12, 2012 #5
    Thank you very much!
     
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