Projectile motion velocity question

  • Thread starter J-dizzal
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  • #1
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Is the x component of the initial velocity equal to the velocity of the projectile at max height?

v0cosθ0i = vmax heighti
 

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  • #2
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Is the x component of the initial velocity equal to the velocity of the projectile at max height?

v0cosθ0i = vmax heighti

Yes it is. The ##x##-component never changes since there is no acceleration in the ##x##-direction. At maximum height, ##v_y = 0##, so ##\vec{v} = v_0 \cos{\theta_0} \hat{\imath}##.
 
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  • #3
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we are talking in vacuum, right?
 
  • #4
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we are talking in vacuum, right?
yes that is the assumption
 
  • #5
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well if want to solve in real world then you have to consider drag force of air which will act on both x and y component and if wind is also blowing then it will effect the answer more but in ideal case as there is no acceleration along x direcion so dv/dt is 0 so velocity along x (v0 cos(angle of projection from horizontal) does not changes.
 

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