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Projectile motion velocity question

  1. Jun 21, 2015 #1
    Is the x component of the initial velocity equal to the velocity of the projectile at max height?

    v0cosθ0i = vmax heighti
  2. jcsd
  3. Jun 21, 2015 #2
    Yes it is. The ##x##-component never changes since there is no acceleration in the ##x##-direction. At maximum height, ##v_y = 0##, so ##\vec{v} = v_0 \cos{\theta_0} \hat{\imath}##.
  4. Jun 21, 2015 #3
    we are talking in vacuum, right?
  5. Jun 21, 2015 #4
    yes that is the assumption
  6. Jun 21, 2015 #5
    well if want to solve in real world then you have to consider drag force of air which will act on both x and y component and if wind is also blowing then it will effect the answer more but in ideal case as there is no acceleration along x direcion so dv/dt is 0 so velocity along x (v0 cos(angle of projection from horizontal) does not changes.
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