Projectile motion- Deriving the right formular

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SUMMARY

The discussion centers on calculating the height of a cliff from which two projectiles are launched horizontally. Projectile A is launched at 20 m/s and Projectile B at 30 m/s, both from the same height, and they strike the ground after 3.0 seconds. The correct height of the cliff is determined using the formula h = 1/2 * g * t^2, where g is the acceleration due to gravity (approximately 9.81 m/s²). The calculated height is 44 meters, confirming option (2) as the correct answer.

PREREQUISITES
  • Understanding of projectile motion principles
  • Familiarity with the equation h = 1/2 * g * t^2
  • Basic knowledge of kinematics
  • Ability to perform calculations involving gravity (g ≈ 9.81 m/s²)
NEXT STEPS
  • Study the derivation of the projectile motion equations
  • Learn about the effects of air resistance on projectile motion
  • Explore advanced kinematic equations for non-horizontal launches
  • Practice solving real-world problems involving projectile motion
USEFUL FOR

Students studying physics, educators teaching projectile motion concepts, and anyone interested in mastering kinematics and motion analysis.

majormuss
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Homework Statement



Projectile A is launched horizontally at a
speed of 20. meters per second from the top of
a cliff and strikes a level surface below, 3.0 seconds
later. Projectile B is launched horizontally
from the same location at a speed of 30. meters
per second.
Approximately how high is the cliff?
(1) 29 m (3) 60. m
(2) 44 m (4) 104 m

Homework Equations




d=tv

The Attempt at a Solution


On two occasions my answer turn out to be '3' and '4'. but the answer key says it's '2'. I have tried for hours but i can't find the right approach. Please offer me a good explanation of how I should work with this? or u can even give me a link to read more or something.
 
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Use the equation
h = 1/2*g*t^2
 

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