Projectile Motion Distance Calculation

Thread starter chelsea01
Start date May 17, 2019
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Calculation Motion Projectile Projectile motion

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The discussion focuses on calculating projectile motion distance with constant velocity. It emphasizes defining initial positions, x0 and y0, as zero to facilitate solving for distance. Participants suggest that the next step is to calculate the x and y positions at a specific time of 2.9 seconds. The conversation indicates a collaborative approach to solving the problem. Overall, the thread provides guidance on applying basic physics principles to projectile motion calculations.

May 17, 2019

chelsea01

Homework Statement: A projectile is launched at ground level with an initial speed of 46.0 m/s at an angle of 25.0° above the horizontal. It strikes a target above the ground 2.90 seconds later. What are the x and y distances from where the projectile was launched to where it lands?

Relevant Equations: Horizontal Motion(ax = 0)
x = x0 + Vx t
Vx = V0x = Vx = velocity is a constant.

Vertical Motion(assuming positive is up ay = −g = −9.80m/s squared)
y = y0 +1/2 (v0y + vy)t
vy = v0y − gt
(3.39)
y = y0 + v0yt −1/2gt2

This based on velocity being constant. Define x0 and y0 to be zero and solve for the desired quantities.

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May 17, 2019

berkeman

Admin

Welcome to the PF.

Looks good so far. You should be able to solve for x and y at time = 2.9s now...

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