Projectile Motion - Finding theta

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SUMMARY

The discussion focuses on solving a projectile motion problem involving a graphed parabola with time intervals of 0.1000 seconds. Key values identified include total time of flight (Tt) at 2.000 seconds, range (R) at 14.50 cm, and maximum height (H) at 10.00 cm. The equations used are Tt = 2 (V sin θ/g), R = (V² sin 2θ)/g, and H = (V sin θ)²/(2g). The main challenge is determining the initial velocity (V0) and the launch angle (θ) based on the provided data.

PREREQUISITES
  • Understanding of projectile motion equations
  • Familiarity with trigonometric functions, specifically sine and cosine
  • Knowledge of kinematic equations
  • Basic graph interpretation skills
NEXT STEPS
  • Calculate initial velocity (V0) using the equations of motion
  • Determine the launch angle (θ) using the range and height equations
  • Explore the impact of varying launch angles on projectile motion
  • Review the derivation of projectile motion equations for deeper understanding
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Students studying physics, particularly those focusing on kinematics and projectile motion, as well as educators looking for practical examples to illustrate these concepts.

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Homework Statement


Iv'e been given a graphed parabola with each x interval at 0.1000s. From this I need to find R, Tt, H, V0, a and θ.

Homework Equations


Tt= 2 (Vsinθ/g)
R= (V2sin2θ)/g
H=(Vsinθ)2)/2g

The Attempt at a Solution


From observing the graph I know:
dx and dy at every 1/10 of a second.
Tt= 2.000s
R= 14.50cm
H= 10.00cm

From here I have no idea how to find V0 or θ. I'm not sure what one I have to find first in order to get the other. Any help is appreciated.
 
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it sounds like you were given the distance that the object traveled and its max height through this graph

by looking at the x-direction and y-direction separately, you should be able to determine the initial velocity in both the x and y directions
 

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