Projectile Motion Homework: Plane Speed, Decoy Release & Displacement Equations

Click For Summary
SUMMARY

The discussion centers on solving a projectile motion problem involving an airplane releasing a radar decoy. The airplane travels at 180 mi/h (80.45 m/s) at a 30-degree angle, with the decoy striking the ground 2300 ft away. The calculated height of the plane at the time of release is 1657.67 m, and the time the decoy was in the air is 22.95 seconds. Additionally, a secondary problem regarding the acceleration of a sprinter is addressed, yielding an acceleration of 4 m/s².

PREREQUISITES
  • Understanding of projectile motion principles
  • Familiarity with displacement equations
  • Knowledge of unit conversions (e.g., feet to meters)
  • Basic trigonometry for angle calculations
NEXT STEPS
  • Study the derivation of displacement equations in projectile motion
  • Learn about the effects of angle on projectile trajectory
  • Explore unit conversion techniques for physics problems
  • Investigate circular motion and acceleration in sports physics
USEFUL FOR

Students studying physics, particularly those focusing on mechanics and projectile motion, as well as educators looking for practical examples to illustrate these concepts.

Sympathy
Messages
10
Reaction score
0

Homework Statement


a certain airplane has a speed of 180 mi/h and is diving at an angle of 30.0 degrees below the horizontal when a radar decoy is released. The horizontal distance between the release point and the point where the decoy strikes the ground is 2300 ft. (a) How high was the plane when the decoy was released? (b) how long was the decoy in the air?


Homework Equations


Displacement equations


The Attempt at a Solution



I tried converting every distance unit to meters and got the velocity was 80.45 m/s
and the horizontal vel = 69.67 m/s
vertical vel = 40.225 m/s

but then I had to find part b before I could answer part a?

p.s. the answers I got were a) 1657.67m and b) 22.95 sec.

i don't think this is right
 
Physics news on Phys.org
oh and 2nd problem

a) What is the acceleration of a sprinter running at 10 m/s when rounding a bend with a turn radius of 25m? b)In what direction does the acceleration vector point?

I got a), it's 4 m/s2. But what does b) asking?
 
Your velocity components seems to be correct, but your dropping distance not.

Show us how you calculated a) with the substituted values. Hint: Use the horizontal speed to calculate the dropping time.
 

Similar threads

Replies
16
Views
3K
Replies
4
Views
2K
  • · Replies 3 ·
Replies
3
Views
2K
  • · Replies 3 ·
Replies
3
Views
4K
  • · Replies 11 ·
Replies
11
Views
2K
  • · Replies 1 ·
Replies
1
Views
2K
  • · Replies 3 ·
Replies
3
Views
6K
  • · Replies 6 ·
Replies
6
Views
2K
  • · Replies 1 ·
Replies
1
Views
2K
  • · Replies 9 ·
Replies
9
Views
3K