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A) Show that the elevation angle B of the highest point as seem from the launch point is related to Ao by tanB = (1/2)tanAo

B) Calculate B for Ao = 45 deg

So

I figure at the highest point, Vy must equal 0.

let H be height of launch

let R by range of launch

so tanB = H/(1/2)R

and tanB = (1/2)tanAo

therefore

H/(1/2)R = (1/2)tanAo

tanAo = H/(1/4)R

I'm not sure how to proceed, do I want to derive H or R in terms of velocity/acceleration?

Thanks,