Projectile Motion, only given horizontal distance

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To calculate the initial speed of a football thrown 85.8 meters without a specified angle, it's important to recognize that multiple initial velocities are possible depending on the launch angle. Assuming a 45-degree angle simplifies the problem, as this angle maximizes range in projectile motion. The discussion highlights the confusion caused by the lack of explicit angle information in the homework question. After assuming the angle, the user successfully solved the problem using the range formula. This approach demonstrates the importance of making reasonable assumptions in physics problems when information is incomplete.
PhysicsMan999
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Homework Statement


The longest pass in history is 85.8m. Ignoring any air resistance effects, calculate the initial speed of football.

Homework Equations


Vx=Vo cosΘ
x=VcosΘt
Vy=VosinΘ -gt
y= VosinΘt - 0.5gt^2

The Attempt at a Solution


I really don't know what to do here. I've looked through all my notes and book and haven't seen any problems like this (with no angle). Every time I try to rearrange and substitute equations I still end up with 2 unknowns. It would be great if someone could point me in the right direction.[/B]
 
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Are you sure 85.8m is all you're given? There will be many answers if you only have 85.8m as the distance because the magnitude of the initial velocity will be dependent on the angle. In this case, I'd first ask your teacher and if not, just choose a random angle 90>x>0 (most likely 45 degrees for simplicity).
 
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Yeah that's all the question had. You might be right about that, the "longest pass in history" could be implying a 45 degree angle since I remember him saying that a 45 angle would give the greatest range. It would have been nice for him to actually state that in the question though. I'll try to work it out tomorrow (it's 1 AM and I've been pondering it for far too long tonight) like that and see how it goes. Thanks for the help!
 
Np, good night.
 
Well I managed to work it out, you were right! I assumed an angle of 45 degrees and got the right answer pretty quickly after that using the range formula. Really appreciate the guidance!
 
Yep I would assume that assuming 45 degrees would be the best way to approach the problem. Given the way its worded though, it would be a bit confusing.
 
The book claims the answer is that all the magnitudes are the same because "the gravitational force on the penguin is the same". I'm having trouble understanding this. I thought the buoyant force was equal to the weight of the fluid displaced. Weight depends on mass which depends on density. Therefore, due to the differing densities the buoyant force will be different in each case? Is this incorrect?

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