(adsbygoogle = window.adsbygoogle || []).push({}); 1. The problem statement, all variables and given/known data

A ball is thrown leftward from the left edge of the roof, at height h above the ground. The ball hits the ground 1.60 seconds later, at distance d = 24.0 m from the building and at angle theta = 55 degrees with the horizontal. (a) Find h. What is the (b) magnitude and (c) angle relative to the horizontal of the velocity at which the ball is thrown?

We know that the impact angle is theta = 55 degrees

x distance is 24.0 m

time for the ball to hit the ground is 1.60 seconds.

2. Relevant equations

y-y_{0}= v_{0}sin(theta)t - gt^{2}/2

x-x_{0}= v_{0}cos(theta)t

V_{x}= v_{0x}t

V_{y}= v_{0y}t

v_{0x}= v_{0}cos(theta)

v_{0y}= v_{0}sin(theta)

3. The attempt at a solution

My first step was to solve for h. What I did was reverse the motion so instead of tossing the ball from the rough, we tossed it from the ground. I made the impact point the origin (0,0). Next I took my second equation and solved it for v_{0}which gave me x-x_{0}/ cos(theta)t = v_{0}. I plugged that into the first equation and then solved for y which gave me the value 21.73 m.

Now, here is where I get lost. I'm not sure exactly what to solve for. I thought maybe if I solved the equation backwards like I did for height I could find the impact velocity and make that my initial velocity. The problem is I don't know where to start. Any suggestions would be appreciated for sure!

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# Homework Help: Projectile Motion, Physics I with Calc. I

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