Projectile Motion Problem This problem is completely evading me.

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William Tell needs to hit an apple from 27.8 m away with an arrow traveling at 34.6 m/s. The calculations involve determining the angle of projection using the formula sin 2(theta) = Rg/(initial velocity squared). The user initially found angles of 6.58 degrees and 84.3 degrees, but the homework engine marked them incorrect. A suggestion was made that the answer might need to be in radians, approximately 0.114 rad, which aligns with the first angle found. The discussion highlights confusion over the expected number of solutions for the angle.
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William Tell must split the apple atop his son's head from a distance of 27.8 m. When he aims directly at the apple, the arrow is horizontal. At what angle must he aim it to hit the apple if the arrow travels at a speed of 34.6 m/s?

This sounds extremely simple, and I thought I got the answer at first. However, the homework engine at my college keeps saying I got the answer wrong.

Here's how I did it:

Vyot - 1/2gt^2 = 0

I solve for t, and get t=0 and t=2Vyo/g

I plug the second t in the x-cordinate for horizontal motion.

R = x = Vxot = Vxo(2Vyo/g) = (2VxoVyo)/g = (2V^2o sin(theta)o cos(theta)o)/g)

Eh, the work is messy but I'll skip down to my final deriviation and that is:

sin 2(theta) = Rg/(velocity initial squared)
(This is a common formula and the book uses this same formula to solve similar problems like this. And the funny thing is that I can follow their answers using that equation, but I apparently don't get a correct answer when I'm using it in this problem.)

I plugged in all the information I got and received 6.58 degrees and 84.3 degrees. There are two answers, and I typed both of them in the homework engine, and it said they were wrong. What am I doing wrong?
 
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Here's a picture just to help.

This is basically what I'm doing and I'm still apparently getting the wrong answer, lmao!

http://img158.exs.cx/my.php?loc=img158&image=0501252243177jy.jpg
 
I think your answer is correct. Maybe the answer is supposed to be in radians?
 
The answer should be roughly 0.114 rad which is approx.the number you found (+6.5°).

Daniel.


P.S.How did you find 2 solutions??
 
Last edited by a moderator:
dextercioby said:
The answer should be roughly 0.114 rad which is approx.the number you found (+6.5°).

Daniel.


P.S.How did u find 2 solutions??

Oops... I didn't notice the second solution he had. The 84.3 degrees is wrong. Is the computer expecting two answers?
 
The book claims the answer is that all the magnitudes are the same because "the gravitational force on the penguin is the same". I'm having trouble understanding this. I thought the buoyant force was equal to the weight of the fluid displaced. Weight depends on mass which depends on density. Therefore, due to the differing densities the buoyant force will be different in each case? Is this incorrect?

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