Projectile Motion Question (Envelope of trajectories) query

  • Thread starter Thread starter laser
  • Start date Start date
  • Tags Tags
    Projectiles
Click For Summary

Homework Help Overview

The discussion revolves around a projectile motion problem involving the trajectory of a ball and its interaction with a wall. Participants are examining two similar questions, one posed by a professor and another found in a textbook, questioning their equivalence and the correctness of their respective solutions.

Discussion Character

  • Mixed

Approaches and Questions Raised

  • Participants are exploring the implications of setting the discriminant of a quadratic equation to zero, questioning what this means for the trajectory of the ball and its peak height relative to the wall.
  • Some participants express confusion about the handwritten solutions and the reasoning behind the methods used, particularly regarding the conditions under which the ball just clears the wall.
  • There is a discussion about the differences between minimizing velocity and ensuring the projectile clears the wall, with references to specific angles and conditions for the trajectory.

Discussion Status

The conversation is ongoing, with participants actively questioning each other's reasoning and interpretations. Some guidance has been offered regarding the implications of the discriminant and the conditions for the projectile's trajectory, but no consensus has been reached on the correctness of the solutions presented.

Contextual Notes

Participants are working under the constraints of homework rules, which may limit the information they can share or the methods they can use. There is also a reference to a specific example from the professor that may not align with the current problem being discussed.

  • #31
PeroK said:
Yes.
hmm, can't see the algebra for some reason.
 
Physics news on Phys.org
  • #34
erobz said:
I think we are talking about the solutions to different problems. I plotted them, these aren't equivalent expressions.

$$ \sqrt{2gh+\frac{gl^2}{2h}} \neq \sqrt{gh + g \sqrt{h^2 + l^2} } $$
Yes,there are two different problems in this thread.
 
  • Like
Likes   Reactions: erobz
  • #35
I think there is three.
 
  • #36
kuruman said:
Below I am addressing the second question, 3.6.
But 3.6 explicitly asks for a trajectory that “just clears the wall at the top of its parabolic motion”. This to me suggests that they are not asking for the smallest possible speed, but the lowest speed that clears the wall with the apex just above it. This is also consistent with
kuruman said:
the optimization condition yields v0=gh+gl2+h2 which verifies what you got.
not being one of the multiple choice options.
 
  • #37
I think problem (b) and problem 3.6 from post #1 are equivalent questions. The projectile apex ##h## of each problem is ##\ell## distance away from the thrower, and it will land ##\ell## distance past the wall in both cases.
 
  • Like
Likes   Reactions: Orodruin
  • #38
erobz said:
I think problem (b) and problem 3.6 from post #1 are equivalent questions. The projectile apex ##h## of each problem is ##\ell## distance away from the thrower, and it will land ##\ell## distance past the wall in both cases.
Quite so. But the OP applied a method (zero determinant) used by @laser's prof in a problem that asked for minimum velocity. This is what led to the right hand expression in your post #33.
That the method works for that problem can be seen thus:
Minimising y wrt x in ##ax^2+xy+c=0## produces ##2ax=-y##, whence ##y^2=4ac##.
 
  • #39
haruspex said:
That the method works for that problem can be seen thus:
Minimising y wrt x in ##ax^2+xy+c=0## produces ##2ax=-y##, whence ##y^2=4ac##.
I don't follow, what is meant by the method works? They yield different expressions for ##v##.

laser said:
Interesting, I just rechecked the example the professor did, and indeed, that question did ask for the "minimum speed"! Here was the exact wording:

1703016628381.png


The method that the OP and @kuruman use solves this ^^ problem, which is equivalent to neither problem in the opening post.
 
  • #40
erobz said:
I don't follow, what is meant by the method works? They yield different expressions for ##v##.
Avoiding the pronouns, that the determinant method works for the minimum velocity problem. It gives the wrong answer for both questions in post #1.
 
  • Like
Likes   Reactions: erobz
  • #41
Orodruin said:
But 3.6 explicitly asks for a trajectory that “just clears the wall at the top of its parabolic motion”. This to me suggests that they are not asking for the smallest possible speed, but the lowest speed that clears the wall with the apex just above it. This is also consistent with

not being one of the multiple choice options.
Yes, they are equivalent. The funny thing is that I initially confirmed one of the choices, but then I got turned around by the phantom problem of optimizing ##v_0##.
erobz said:
@kuruman says they are addressing ##\dots##
Thank you for being considerate. For the record, my preferred pronouns are "he, him, his."
 
  • #42
I agree with @erobz that there are three problems mentioned here:
1. Problem (b) in post #1.
2. Problem 3.6 in post#1.
3. The professor's problem in post #13.

Small wonder I got confused. To avoid further confusion, can we refer to them respectively as (b), 3.6 and prof? I think we all agree that the first two are equivalent but the third is not for reasons already explained.
 
  • Like
Likes   Reactions: erobz
  • #43
kuruman said:
I agree with @erobz that there are three problems mentioned here:
1. Problem (b) in post #1.
2. Problem 3.6 in post#1.
3. The professor's problem in post #13.
Yes.

kuruman said:
Small wonder I got confused. To avoid further confusion, can we refer to them respectively as (b), 3.6 and prof? I think we all agree that the first two are equivalent but the third is not for reasons already explained.
Indeed.
 

Similar threads

  • · Replies 18 ·
Replies
18
Views
2K
  • · Replies 8 ·
Replies
8
Views
3K
  • · Replies 21 ·
Replies
21
Views
1K
Replies
19
Views
3K
  • · Replies 13 ·
Replies
13
Views
1K
  • · Replies 1 ·
Replies
1
Views
2K
Replies
21
Views
3K
  • · Replies 8 ·
Replies
8
Views
6K
  • · Replies 9 ·
Replies
9
Views
1K
  • · Replies 3 ·
Replies
3
Views
3K