Projectile Motion: How Far Will a Seed Travel at a Given Angle and Velocity?

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To determine how far a seed travels when ejected from a height of 1.4 m at a velocity of 3.0 m/s at a 20-degree angle below the horizontal, the velocity must be broken into x and y components. The x-component is calculated as 3cos(20), while the y-component is 3sin(20). The quadratic equation is used to find the time of flight, with the equation set up as 0 = 1/2(9.8)t^2 + 3sin(20)t + 1.4. The total horizontal distance can then be calculated by multiplying the x-component by the overall time. This approach provides a systematic method to solve the projectile motion problem.
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Homework Statement



You spit a seed from a height of 1.4 m above the ground, at a velocity of 3.0 m/s at an angle of 20 below the horizontal. How far from you does it land?

Homework Equations



vxo= vo(cos20)
vyo=vo(sin20

The Attempt at a Solution



not sure where to start..
 
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Break the overall velocity into x and y components.

x direction <=> 3cos(20) = ?

y direction <=> 3sin(20) = ?

Use quadratic equation to find the overall time.

0= 1/2 (9.8)t^2 ( value for a) + 3sin(20)t (value for b) + 1.4 (value for c)

Total distance traveled can be calculated by ( 3cos(20) x ( overall time))

P.S. Next time , at least try to initiate the attempt.

Good luck.
 
Last edited:
The book claims the answer is that all the magnitudes are the same because "the gravitational force on the penguin is the same". I'm having trouble understanding this. I thought the buoyant force was equal to the weight of the fluid displaced. Weight depends on mass which depends on density. Therefore, due to the differing densities the buoyant force will be different in each case? Is this incorrect?

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